So this is how you pass arrays to functions!

You just use pointers to pass arrays of any size to a function/method?

something I found (I did not write this)

Code:

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        // This takes a list of vertices and the vertex count to determine if the camera's
        // shere has collided with them.
        void CheckCameraCollision(CVector3 *pVertices, int numOfVerts);
        //USE A POINTER TO PASS IN AN ARRAY OF AN UNSPECIFIED SIZE

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Do you always have to declare the array using pointers in order to pass the array to a function

For example the array that is actually passed to this function when it is called is declared as:
CVector3 *g_vWorld=NULL;

No, you can pass it without it being a pointer, but you would be makeing a copy of the array. Just like when you pass a non-pointer variable, you are making a local copy of that variable in your function. (unless you pass a reference)

Also, if the array has the ability to provide its element count to you, then there is no need to pass the elements as a seperate parameter.

Nope. Since the argument is a pointer to the type n, it's not neccessary an array. You can pass a single variable as well as a statically or dynamically allocated array:

Code:

---

void MyFunc(int* MyPointer)
{
  ...
}

int main()
{
  int Var1;
  int Var2[32];
  int* Var3 = new int[1024];

  MyFunc(&Var1);
  MyFunc(Var2);
  MyFunc(Var3);

  delete[] Var3;
  return 0;
}

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I don't see why you don't pass the memory address of the arrays to the function.

Quote:

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Originally posted by Shadow12345
I don't see why you don't pass the memory address of the arrays to the function.

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You mean in my example? That's because an array is basically a pointer to a chunk of memory, thus when you pass the "array" you actually pass a pointer to it.