I am writing a program that creates an int array, takes ints from the user, and determines the min, max and average of all values. This part I can do. What I am having trouble with is that the values entered can only be positive. So if the user enters a negative number I have to send an error message to the screen saying int must be positive, which I have done already. I can't figure out how to keep from counting that value in my counter and not include the negative number in my calculations for the minimum.

Here is the code:

Thanks for any help.Code:#include <iostream> using namespace std; int main() { int nums[100]; int i, max, min, total =0, count = 1; double avg; cout << "Enter positive interger numbers (or -1 to quit): " << endl; cin >> nums[0]; if (nums[0] == -1) { cout << "Bye."; return 0; } if (nums[0] < -1) cout << "********ERROR SKIPPED ENTRY********" << endl << "Number must be positive"; max = nums[0]; min = nums[0]; total = nums[0]; while (i > -1) { for (i = 1; i < 100; i++) { cin >> nums[i]; if (nums[i] < -1) { cout << "********ERROR SKIPPED ENTRY********" << endl << "Number must be positive"; count = count -1; total = total - i; } if (nums[i] == -1) { cout << "Read in " << i << " values." << endl; cout << "Minimum value: " << min << endl; cout << "Maximum value: " << max << endl; cout << "Average: " << (total +1) / i << endl; cout << count << endl; cout << total; return 0; } else { if (nums[i] > max) max = nums[i]; if (nums[i] < min) min = nums[i]; count ++; total = nums[i] + total; } } } return 0; }