2D Arrays

[minesweeper]

This might be a really stupid question that I will kick myself for not knowing the answer but why, from the output of this program is the first number 4 times the second number?

#include <iostream.h>


int main()
{
	const int sizea(5), sizeb(5);
	int a[sizea][sizeb];

	
	for (int i=0;i<=sizea-1;i++)
	{
		for (int o=0;o<=sizeb-1;o++)
		{
			a[i][o]=1;
		}
	}
	
		cout<<sizeof(a)<<endl;
		cout<<(sizea*sizeb)<<endl;
		return 0;
}

[Cshot]

Because sizeof(a) = sizeof(int) * sizea * sizeb = 4 * 5 * 5

[minesweeper]

Yeah, you're right, thanks. I'm having one of those dumb days!!

[elad]

the operator sizeof() returns the number of bytes in a particular variable, not the number of elements in the array you are using it on. To get the number of elements that could be stored in the array called a using the sizeof() operator use the following syntax: sizeof(a)/sizeof(sizea) where a is a 2D array of type int and sizea is an int.