Thread: Question

Hi

I'm writing a very simple program. Im supposed to create an object that contains an array in it.
For instance:


calss intArr
{
public:
intArr(int size);
int operator [] (int index);
int * Arr;

private:
int size

}

the point of this small exercise is to be able to do the following:


void main()

intArr mainArr(10);

mainArr[3]=7;


the idea is to be able to refer to a specific element just like any other built in type array, instead of having to write: mainArr.Arr[3]=7



However, whenever I perform this assignment I get a compilation error:
left operand must be l-value.
When I write the following : i=mainArr[3] there is no problem.


Here's my operator [] implementation :


int intArr operator [] (int index)
{

return Arr[index]
}



what am I doing wrong here?

thanks

Gozlan

Lots of typos for a start..

Also, operator[] was not shown to be a member of intArr in your code.....also if you want to assign to the array like that, then you need to return a reference....not a normal int. Also, you dont show to be managing memory.....

Here's a rather rushed example;

Code:

class intArr
{
public:
	intArr(int size);
	~intArr(){delete[] Arr;}
	int& operator [] (int index);

private:
	int size;
	int * Arr;

};

intArr::intArr(int sz){
	Arr = new int[sz];
	if(!Arr){/*Error management here*/}
}

int& intArr::operator [] (int index)
{
	return Arr[index];
}


int main(){

	intArr mainArr(10);

	mainArr[3] = 7;

	std::cout << mainArr[3];

}

Thanks Fordy!

It did the trick...


cheers

gozlan