convert queue into a stack

I am a newbie so bear with me. Can anyone give me a simple sample code of how to empty a queue and put the contents into a stack. I need to check if the stack has room for the contents each time as well as check when the queue is empty. This can be in one function and simple just so I get an idea. Thans in advance.

Ok, two things here:

1. I'm am posting this because it appears that you are posting a homework assignment or other project and you are asking for someone else to do all of the work.

Please don't ask people to do all your work for you, See the announcement on Homework at the top of the forum to see what is acceptable ro PM. Basically people are happy to help, but they're not going to do it all for you.

Show us what you've got, show your code (using code tags), or where you're confused and someone will be happy to help you I'm sure. If it's something that you absolutely don't understand how it works, like you have no clue how qsort works, then ask a general question about the function and I'm sure someone will explain it. Though they may not give you all of the code for it, but someone will explain the concept.



2. This is a fairly common topic, I know I've seen it quite a few times in the past. Why don't you use the board's Search function and look for it.

If you honestly don't understnad the concept then try searching and if you still you have no clue then say so. I'm sure soeone will point you in the right direction.

Then try your own, if you hit a brickwall, come back, someone will help

Good Luck,
Kermi3

PS. I know some of that post was repetititive some of it was a "form" post hehe. Sorry for making you read things repetitively.

I am using STL, here is what I have so far. Somehow I need to check if the stack is full or not before pushing. Or I need to determine what the overflow error returns and handle it somehow.

Stack<int> stackNbrs;
Queue<int> queueNbrs;

while(!queueNbrs.empty()){
stackNbrs.push(queueNbrs.retrieve());
queueNbrs.serve();
}

One solution is to push one element into the second object.

- pop x
- push x into y

Kuphryn