simple problem

This is a discussion on simple problem within the C++ Programming forums, part of the General Programming Boards category; how do you make an integer accept a decimal value? I know i knew this, but now...and it's not in ...

  1. #1
    none
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    simple problem

    how do you make an integer accept a decimal value?

    I know i knew this, but now...and it's not in the faq

    somebody please help

  2. #2
    Registered User Azuth's Avatar
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    Use a float, not an int?
    Demonographic rhinology is not the only possible outcome, but why take the chance

  3. #3
    TransparentMember correlcj's Avatar
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    how do you make an integer accept a decimal value?
    use a double
    eg;
    double n = 6.0

    U R right, pretty simple, my friend
    cj
    "Be formless, shapeless, like water... You put water into a cup, it becomes the cup, you put water into a bottle, it becomes the bottle, you put it in a teapot, it becomes the teapot... Now water can flow, or it can crash, be water my friend."
    -Bruce Lee

  4. #4
    RoD
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    Redundantly Redundant RoD's Avatar
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    u could cast it.

    int variable;
    int final;

    final = double(variable);

  5. #5
    End Of Line Hammer's Avatar
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    Originally posted by Ride -or- Die
    u could cast it.

    int variable;
    int final;

    final = double(variable);
    errr... no. final is an int and will only ever hold an int value. The use of the implied cast is also incorrect, you meant this:
    >final = (double)variable;
    ... but it wouldn't store the digits to the right of the decimal point, if there were any. Of course, there can't be any though, as variable is an int as well.
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  6. #6
    none
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    wow....

    thanks for all the alternatives, but i think i'll stick with "float".

    Sorry to trouble you with such a simple question.

  7. #7
    S Sang-drax's Avatar
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    Originally posted by Hammer

    >>final = double(variable);
    The use of the implied cast is also incorrect, you meant this:
    final = (double)variable;
    I don't see anything wrong with double(variable).
    It is C++-style casts.

    Nevertheless, the cast is useless.
    Last edited by Sang-drax : Tomorrow at 02:21 AM. Reason: Time travelling

  8. #8
    Just a Member ammar's Avatar
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    I don't think we can cast with: double(variable).
    it's just like:
    Code:
    int x=5;
    double y=9;
    
    x=y;
    isn't it?

  9. #9
    End Of Line Hammer's Avatar
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    >>It is C++-style casts.
    Oops, you're right, I didn't spot that

    >>Nevertheless, the cast is useless.
    That was my main point too.
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

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