Hi, I need to be pointed towards the correct way to express,
a greater percent chance of something happending.
For example:
a and b are playing cards and a has a 60% chance of winning.
and the wins are generated by rand.(got that part) it's just
the percentages
Thanks
Michele
One easy way is to generate random numbers from 1-100. Anything from 1-60 inclusive would mean a wins, and anything else means b wins.
Try not.
Do or do not.
There is no try.
- Master Yoda
The random number will always be random, so you need to make the condition like what Cshot said...
i neeed something
a little more specific
i thought i could do something like this:
where i assigned the percentages to a and b.Code:#include<iostream> #include<cstdlib> #include<ctime> #include<iomanip> #include<iostream> #include<fstream> using namespace std; //function prototype int pp (int); int score = 0; void main() { ofstream outfile("A:\\0F1017_6_2.txt"); if(!outfile){ cerr << "Cannot open output file" << endl; } srand((unsigned) time(0)); int a = 0(.56); int b = 0(.44); int aa = 0; int bb = 0;
it seems to work....
what do you think?
michele
