Easy Question

This is a discussion on Easy Question within the C++ Programming forums, part of the General Programming Boards category; Hi everyone, im new to programming and am taking it at school this year. Heres an easy question but im ...

  1. #1
    Bryan
    Guest

    Easy Question

    Hi everyone, im new to programming and am taking it at school this year.
    Heres an easy question but im stuck on what to do.

    I need to know what code to write so that if a person selects "Yes" they are dropped out of a loop but if they select no the loop continues. How would i go about doing this?

    Heres the code im working with

    if (yesno==1);
    {
    cout<< "Thank You";
    }
    if (yesno==2)
    {
    cout<< "Please Enter your info again";

    As i said i need it so if the person picks yes they get dropped out of the loop but if the answer is no the loop continues.

  2. #2
    Hamster without a wheel iain's Avatar
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    #define yes 1
    #define no 0

    while (yesNo!=yes)
    { code}

    //loop exit code here
    Monday - what a way to spend a seventh of your life

  3. #3
    Bryan
    Guest
    sorry i didnt explain properly, i need to know the code that will actually exit out of the loop if a person picks yes

  4. #4
    Banned master5001's Avatar
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    This isn't the best code but you can work with it.
    Code:
    enum choice {NO, YES};
    
    int main(void) {
        enum choice yes_no;
    
        while(0) {
            yes_no = (getchar() == 'y')?YES:NO;
            if(yes_no == YES)
                 break;
        }
        return 0;
    }

  5. #5
    End Of Line Hammer's Avatar
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    >>while (0)
    That won't work too well
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  6. #6
    Just a Member ammar's Avatar
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    You can use:
    Code:
    break;
    or you can use:
    Code:
     exit(0)
    to exit the whole program.

    Note:
    exit(0) : is used to indicate the program was terminated normally.
    exit(1) : is used to indicate the prgoram was terminated due to an error.

  7. #7
    Registered User
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    In Iaian's example, if the answer is yes, the loop automatically exits. At the end of your code in the loop brackets, get input from the user for yesno (1 or 2). If they answer 1 for yes, the loop will exit when the while statement checks the answer.
    Anything besides 1 will keep the loop going. 3, 10, abc, etc. You could put some error checking in for invalid input.
    Truth is a malleable commodity - Dick Cheney

  8. #8
    Registered User GreenCherry's Avatar
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    Code:
    if (yesno==1);
    {
    cout<< "Thank You";
    break;
    }
    if (yesno==2)
    {
    cout<< "Please Enter your info again";
    ...
    This is probably simple enough for you to understand. If you want it to end the program after it says "Thank You" then use return 0.
    I have a rabbit in my pants! Please be happy for me.

  9. #9
    Bryan
    Guest
    thanks ammar, "break;" was exactly what i needed

  10. #10
    Carnivore ('-'v) Hunter2's Avatar
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    Another solution would be to make it a while loop, as iain said.
    PHP Code:
    #define YES true
    #define NO false

    char input;
    bool yesno NO;

    while(
    yesno != YES//so it'll loop until yesno is YES (duh)
    {
       
    cin >> input;
       if(
    input == 'y')  //if the input is yes, then change yesno to YES
          
    yesno YES;
       else  
    //otherwise, threaten them :p
          
    cout << "Sorry, I don't take no for an answer.\n";
    }
    cout << "Thank you!"//Always be polite! 
    Just Google It. √

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  11. #11
    moi
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    Originally posted by iain
    #define yes 1
    #define no 0

    while (yesNo!=yes)
    { code}

    //loop exit code here
    this code fragment will do everything but work
    hello, internet!

  12. #12
    Carnivore ('-'v) Hunter2's Avatar
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    lol why, because the exit code is outside the loop? So what? I'm out of the loop a lot and I still work
    Just Google It. √

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  13. #13
    moi
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    Originally posted by Hunter2
    lol why, because the exit code is outside the loop? So what? I'm out of the loop a lot and I still work
    heh
    hello, internet!

  14. #14
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    is your life just one big syntax error?
    mine is.
    --Cid666

  15. #15
    Registered User Kirdra's Avatar
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    Maybe this is a bit clearer:

    Code:
    #include <iostream>
    using namespace std;
    
    int main()
    {
        int loop = 0;
        
        do
        {
            cout << "Enter a number: ";
            int num;
            cin >> num;
            
            if(num == 1)
            {
            cout << "One!, thats my favorite number.\n";
            loop = 1;        //Break the loop
            }
            
            else
            {
            cout << "Hmm, ok... try again.\n";
            }
            
        } while(loop == 0);
        
        return 0;
    }

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