OK, here's my problem: I have a class TLine that is defined as follows:
it isn't everything, but thats the essentials. A TPoint is defined as follows:Code:class TLine { public: /* . . . */ private: TPoint P1, P2; };
Code:
This is a discussion on How to decide if four lines form a square? within the C++ Programming forums, part of the General Programming Boards category; OK, here's my problem: I have a class TLine that is defined as follows: Code: class TLine { public: /* ...
OK, here's my problem: I have a class TLine that is defined as follows:
it isn't everything, but thats the essentials. A TPoint is defined as follows:Code:class TLine { public: /* . . . */ private: TPoint P1, P2; };
Code:
Check if the points of the different lines equals, so that a square is formed.
Ie: Check if one point of the line L1 matches any of the other lines (L2-L4).
If it do, check if that line's (L2) second point matches any of the remaining lines (L3-L4).
If it do, check if that line's (L3) second point matches the remaining lines (L4) points.
If it do, check if L4's second point matches L1's first point.
I suggest parting up this problem in smaller pieces, like:
Point CheckIfPointEqualsAnyOfLinesPoints(Point P, Line L);
bool IsThePointItsFirstOrSecondPoint(PointP, Line L);
...or whatever!
MagosX.com
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Thanx for the help - and yes, sorry about the missing part - but I see you got the gist of it! :-).
Anyways, what I really wanted to know: Isn't there a simpler (i.e. shorter, perhaps iterative?) way of doing it?
Its simple enough to put the four lines in an array. But when I do that, I find it necessary to work with vectors and dot products, and the code just keeps on becoming longer!
However, I think that the points approach is probably best.
Going to be one hell of an if statement!
You simply need two nested for-loops. Take a look a this code:
(Why would I write all this, you ask? Well, sometimes it's really fun to solve mathematical problems... Am I sick? )
<edit>
I'm using conio.h for getch(). If you don't use Borland, simply remove those two lines
</edit>
Code:#include <iostream.h> #include <conio.h> #define NO_POINT 0 #define FIRST_POINT 1 #define SECOND_POINT 2 #define SQUARE true #define NOT_SQUARE false //+----------------------------------------------------------------------------- //| Point structure, a point is defined as a coordinate (In a 2D room) //+----------------------------------------------------------------------------- typedef struct { int Xpos; int Ypos; }POINT; //+----------------------------------------------------------------------------- //| Line structure, a line is defined as two points //+----------------------------------------------------------------------------- typedef struct { POINT Point1; POINT Point2; }LINE; //+----------------------------------------------------------------------------- //| Overloads the == operator, to easily check if two point are the same //+----------------------------------------------------------------------------- bool operator ==(POINT P1, POINT P2) { return ((P1.Xpos == P2.Xpos) && (P1.Ypos == P2.Ypos)); } //+----------------------------------------------------------------------------- //| Creates a point out of 2 integers (X and Y) //+----------------------------------------------------------------------------- POINT CreatePoint(int X, int Y) { POINT TempPoint; TempPoint.Xpos = X; TempPoint.Ypos = Y; return TempPoint; } //+----------------------------------------------------------------------------- //| Creates a line out of 2 points //+----------------------------------------------------------------------------- LINE CreateLine(POINT P1, POINT P2) { LINE TempLine; TempLine.Point1 = P1; TempLine.Point2 = P2; return TempLine; } //+----------------------------------------------------------------------------- //| Checks if a point belong to a line, and which position it has //+----------------------------------------------------------------------------- int PointInLinePosition(POINT P, LINE L) { if(P == L.Point1) return FIRST_POINT; else if(P == L.Point2) return SECOND_POINT; else return NO_POINT; } //+----------------------------------------------------------------------------- //| Returns a specific point in a line //+----------------------------------------------------------------------------- POINT GetPointInLine(LINE L, int Position) { if(Position == FIRST_POINT) return L.Point1; else return L.Point2; } //+----------------------------------------------------------------------------- //| Returns the other point position in a line //+----------------------------------------------------------------------------- int GetOtherPosition(int Pos) { if(Pos == FIRST_POINT) return SECOND_POINT; else if(Pos == SECOND_POINT) return FIRST_POINT; else return NO_POINT; } //+----------------------------------------------------------------------------- //| Main function //+----------------------------------------------------------------------------- int main() { //A square consists of 4 lines LINE Square[4]; //Creates a valid square Square[0] = CreateLine(CreatePoint(3, 3), CreatePoint(12, 3)); Square[1] = CreateLine(CreatePoint(12, 3), CreatePoint(12, 12)); Square[2] = CreateLine(CreatePoint(12, 12), CreatePoint(3, 12)); Square[3] = CreateLine(CreatePoint(3, 12), CreatePoint(3, 3)); //Stores if a certain line has been checked bool LineChecked[4] = {true, false, false, false}; bool Result = SQUARE; int LastPointPosition; POINT LastPoint; //Check if the first three connections are correct LastPoint = GetPointInLine(Square[0], FIRST_POINT); for(int LoopThreeTimes = 0; LoopThreeTimes < 3; LoopThreeTimes++) { for(int i = 0; i < 4; i++) { //Only check with the lines not already checked if(LineChecked[i] == false) { //Try to find a matching point in the line LastPointPosition = PointInLinePosition(LastPoint, Square[i]); if(LastPointPosition != NO_POINT) { //Mark this line as checked, since we got a match LineChecked[i] = true; LastPoint = GetPointInLine(Square[i], GetOtherPosition(LastPointPosition)); i = 4; } else { //If you reached the last element without a match, it can't be a square if(i == 3) Result = NOT_SQUARE; } } } } //If the first three connections are correct, check if the fourth //is too (the last one, connected between the first and fourth). if(Result == SQUARE) { if(PointInLinePosition(LastPoint, Square[0]) == NO_POINT) Result = NOT_SQUARE; } //Print the results if(Result == SQUARE) cout << "The lines form a square!" << endl; else cout << "The lines does NOT form a square!" << endl; getch(); return 0; }
Last edited by Magos; 10-01-2002 at 09:49 AM.
MagosX.com
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Teach a man to fish and you feed him for a lifetime.
Note:
My example just tests if the lines are ordered as a "circular list", so the shapes below will also count as a valid square. Didn't think of that when writing the example. Sorry!
Code:¤ = Point ¤------¤ \ / \ / \/ /\ / \ / \ ¤------¤ ¤ |\ | \ | ¤ | \ | \ ¤-----¤
Last edited by Magos; 10-01-2002 at 10:30 AM.
MagosX.com
Give a man a fish and you feed him for a day.
Teach a man to fish and you feed him for a lifetime.
The square problem is part of a larger system - you can be sure you will be credited! Seeing as how the system is object-oriented, I won't be using your code verbatim - but certainly I'll be using it!
Email me here: moebius2day@yahoo.com if you want a copy of the program when it is finished :-)
Thanks again.
PS: Those shapes can be excluded with a little vector algebra (making the lines into vectors and taking their scalar products to determine if they are perpendicular or parallel)
I code.
I think.
Ergo, I think in code.
True! Didn't think of that.PS: Those shapes can be excluded with a little vector algebra (making the lines into vectors and taking their scalar products to determine if they are perpendicular or parallel) [/B]
So, you can use linear algebra for something useful after all
MagosX.com
Give a man a fish and you feed him for a day.
Teach a man to fish and you feed him for a lifetime.