Simple problem for you guys - school proj

Hello, I am having trouble finishing this code, It converts whatever seven letters you type into the corresponding numbers on a phone. example A = "2" D = "3" G="4" ect. So It prompts a user for seven letter and it then outputs the phone number from those numbers. Everything works fine except I can't figure out how to put a dash after the third number. My output looks like this-- 5558888 I need it to output 555-8888. I also need it to print out a "#" if a lowercase letter is inputed. Thanks in advance for any help. Here is my code....

Code:

#include <iostream>
#include <string>

using namespace std;

int main()
{
	int dum = 0;

	string input;
	string bleh;
	string str2 = "ABC", str3 = "DEF", str4 = "GHI",
str5 = "JKL";
	string str6 = "MNO", str7 = "PQRS", str8 = "TUV",
str9 = "WXYZ";


	cout << "Please enter a Seven letter word, all uppercase ";
	getline(cin, input);

	if (input.length() !=7)
	{
		cout << "The word you typed in is not seven characters in length";
	return 1;
	}


	while (dum <= 6)
	{
	bleh = input.substr(dum,1);

	if (str2.find(bleh) != string::npos)
	{
	cout << "2";

	}
	else if (str3.find(bleh) != string::npos)
	{
	cout << "3";

	}

	else if (str4.find(bleh) != string::npos)
	{
	cout << "4";
	}
	else if (str5.find(bleh) != string::npos)
	{
	cout << "5";
	}
	else if (str6.find(bleh) != string::npos)
	{
	cout << "6";
	}
	else if (str7.find(bleh) != string::npos)
	{
	cout << "7";
	}
	else if (str8.find(bleh) != string::npos)
	{
	cout << "8";
	}
	else if (str9.find(bleh) != string::npos)
	{
	cout << "9";
	}

	dum++;

	
}
	return 0;
}

[edit]Code tags added by Hammer. Please use them in future.

u just need a cout after the third number like this:

cout <<"-";

that would go after the third and before the 4th

I'm not following you, put it after the third number? I know that is what I want to do, however the third number changes every time so how do I tell it to put a dash in the 4th space?

After the if else statements that check what number to put, and before the dum++ add these lines:

Code:

if(dum == 2){

cout << "-";

}

So that will output a "-" when dum is equal to 2, which is the third number.

in your output of the third number u want it to be

cout<<"number here"<<"-";

even if your number chnages the "-" will always be there with it....that more clear?

Welcome to the world of parsing! ha. My personal favorite pastime...

Code:

char *ToTele(char input[]){
int i, j;
int length = strlen(input);
char temp[length+1];

 for(i = 0, j = 0; i < length; i++, j++) {
  if(i == 3) {
    temp[j] = '-';
    j++;
    continue;
    }
  if(input[i] >= 'a' && input[i] <= 'z') {
    temp[j] = '#'; 
    }
  else {
  switch(input[i]) {
  case 'A': case 'B': case 'C':
  temp[j] = '1';
  break;
  //...continue like so...
  default:
   i++;
   continue;
  }
 }
 temp[j] = 0;

 return strcpy(input, temp);
}
}

ahhh thank you I only had one "=" in my dum == 2 line, thanks

Sebastiani, your code is not very portable.

Code:

int length = strlen(input);
char temp[length+1];

should be rewritten using new