Not equal to operator NOT working

I have a question about the relational != operator.

First here is part of my code:

Code:

void RuleThree(string word, string target)
{
	string temp;
	int len = word.length()-1;   // Index of last character

	cout << target << endl;

	if (target!="TH" || target!="th")  // here is the problem!!

	{
		temp = word.substr(1,len);
		word = temp + target + "AY";
		cout << word << endl;
	}

} // End function RuleThree

This is simply not working. When my word starts with TH or th, it still accepts the word and goes through the code. When I do this though:

if (target!="TH" || target=="th")

where only one of them is set to not equal to, it works.

The problem is that I have to add more than just the TH and th to the if statement, but when I do, it treats it as an equal to.

I just don't get it.

Any help would be appreciated

>> When my word starts with TH or th, it still accepts the word and goes through the code.

You're testing the whole string, not just the start!

target = word.substr(0,2);

is included in the code in order to test for the first 2 characters. Thanks for your reply!

So does it work?

I'm sorry, no it doesn't work... I've tried to put the substr inside the function as well and it still won't accept the NOT operator. I've put it right before the call to the function (don't know if that's a good thing or not) but at this point I'm trying anything and everything.

I just don't get it, I've never had this problem before.

I'm not sure if this is what you want to use the function for, but anyway:

Code:

#include <string>
#include <iostream>

using namespace std;

void RuleThree(string word, string target)
{
	string temp1, temp2;
	
	int len = word.length()-1;   // Index of last character

	cout << target << endl;

	temp2 = word.substr(0,2);
	
	if (temp2 == "TH" || temp2 == "th")
		return;
	else
	{
		temp1 = word.substr(1,len);
		word = temp1 + target + "AY";
		cout << word << endl;
	}

} // End function RuleThree

int main()
{
	string one = "THAT'S the joint!";
	RuleThree("THAT'S", one);

	return 0;
}

Code:

if (target!="TH" || target!="th")  // here is the problem!!

	{
		temp = word.substr(1,len);
		word = temp + target + "AY";
		cout << word << endl;
	}

Lets asume that target is "th".

After the evaluation of target != "TH" it evalutes true and therefore it doesn´t need to evaluate anymore bacause regardless of the outcome of the second evaluation the condintion is true!

What you inteended to do is that if target doesn´t start with "TH" or "th" then the compound statement should be executed.

Try change it to

Code:

if (!(target == "TH" || target == "th"))
//statement or compound statement

Hope that it solves your problem

THE DOG Thanks for your answer, you actually gave me an idea to make my code better and it worked! I never thought of making more than one target (duh), I think that's where my problem lied.

RIPPER079 Well that answered my question about the not operator, no wonder it didn't work! I will definitely add that one to my notes!! Thank you very much, you not only made me understand it, but it's one I will not ever forget!

Thanks to you both!!!!