Array

[drdroid]

What's wrong with this array? The error is that it can't conver char to char in function main for each lname variable.

#include <fstream.h>
#include <conio.h>
#include <stdlib.h>

void main()
{
	char lname[5];
	lname[0]="T'pnon";
	lname[1]="Nem'on";
	lname[2]="K'nou";
	lname[3]="Clau";
	lname[4]="Tnon";
	cout << lname[1];
	getch();
}

Code tags fixed (they were off by a '/') by kermi3

[hk_mp5kpdw]

You could change char lname[5] to char* lname[5], that should work. Otherwise you are attempting to assign what are essentially pointers to individual characters in the array. That's the problem with what you were trying to do.

[drdroid]

now, that I got that working why when I try and display one of thoughs in another function why would it only display one letter, the first letter of every monster?

[Sang-drax]

Use std::string and your problems will go away.

[hk_mp5kpdw]

How are you trying to display these character strings?

[drdroid]

Heres the code:

#include <iostream.h>
#include <stdlib.h>
#include <conio.h>


int battle(int hp, char monnm, int dmg)
{
	cout << monnm;
	return 0;
}

void main()
{
	int lp=1;
	while(lp!=0)
	{
		int hp=40;
		int dmg=10;
		char* monster[5];
		monster[0]="Spider";
		monster[1]="Goblin";
		monster[2]="Troll";
		monster[3]="Ogre";
		monster[4]="Hound";
		int monpick=rand()%5;
		battle(hp,*monster[monpick],dmg);
		getch();
	 }
}

[drdroid]

what's wrong with this code? it only outputs the first letter of every monster?

[LuckY]

int battle(int hp, char monnm, int dmg)

battle(hp,*monster[monpick],dmg);

Your battle function is asking for a char (a single character) and that is what you are correctly passing when you call it. It should be:

int battle(int hp,const char *monnm,int dmg)