Thread: need your help!

Hi all,
I'm new to C and I have a little problem. I have been trying to figure out for more than 2 days why I get this error : parse error before `]' (with linux gcc compiler) because of this line of code : b = passwd_check(passwd[]); . Anyone knows why?
thanks...

Code:

#include <stdio.h>
#define MAX 100
int passwd_check(char passwd[]);  /*fonction to check if password is right or not*/
main()
{
char passwd[MAX];
int a, b;

for (a = 0; a != MAX && passwd[a - 1] != '\n'; a++)
{
passwd[a] = getchar();
}

b = passwd_check(passwd[]);         /* <-------  this is where I get the error */

if (b == 1)
{
printf("\nRight Password\n");
return 0;
}

else 
{
printf("\nWrong Password\n");
return 0;
}
}

int passwd_check(char passwd[])
{
int c;


if (passwd[0] == 'k' && passwd[1] == '3' && passwd[2] == 'n' && passwd[3] == '\n')
c = 1;

else 
c = 0;
return c;
}

Code tags added by Kermi3

Code:

b = passwd_check(passwd[]);         /* <-------  this is where I get the error */

try passwd instead of passwd[]