Counting Up and Down... time/percent

This is a discussion on Counting Up and Down... time/percent within the C++ Programming forums, part of the General Programming Boards category; I would like to be able to print out a number... count up or down but the problem is I ...

  1. #1
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    Question Counting Up and Down... time/percent

    I would like to be able to print out a number... count up or down but the problem is I don't want to reprint the line every time the number goes up or down one unit. I have heard of clearing the screen every time you reprint the line but I would rather not do that... For example using fdisk or format and it just counts up the percent.

    I don't need to know how to count just how to reprint the variable without reprinting the whole line.

    Thank You

  2. #2
    Just because ygfperson's Avatar
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    look at the \b and the \r special characters
    Code:
    printf("test\b\b");
    this prints "test" then deletes the ending t and s
    \r simply moves the cursor to the beginning of the line.

    if you're not interested in this fairly portable solution, you could look at gotoxy()

  3. #3
    Guest Sebastiani's Avatar
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    int x, y;

    x = wherex(), y = wherey(); //...save coords..

    gotoxy(2, 10); //...go to counter

    printf("%i", count);

    gotoxy(x, y); //...restore old coords...


    ...very non-portable, though. Windows machines...
    Code:
    int main(void){srand(time(0));for(double l=rand(),l0=0,l00=0;;l0+=0.1){for(double l000=0;l000
    <1;l000+=.001,l+=((double)rand()/RAND_MAX)/0x64,l00+=((sin(l*0x8*atan(l0)*l000-(l0*0x8*atan
    (l)))*0.5)+0.5)){l00-=floor(l00);for(size_t l0000=0,l00000=(size_t)(0x50*(l00));l0000<l00000;++l0000
    )putchar(0x20);putchar(0x61+(int)((double)rand()/RAND_MAX*0x1a));putchar('\n');}}return 0;}

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