Does anyone know a function that will convert a decimal integer to a hexidecimal in the form of a string.
so 1 would become "01" or 10 would become "0A"
thanks
This is a discussion on convert a decimal int to hex within the C++ Programming forums, part of the General Programming Boards category; Does anyone know a function that will convert a decimal integer to a hexidecimal in the form of a string. ...
Does anyone know a function that will convert a decimal integer to a hexidecimal in the form of a string.
so 1 would become "01" or 10 would become "0A"
thanks
sprintf(str,"%x",num); //I believe that's right
"You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter
Thanks, could you also tell me how to convert back?
sscanf is the same kind of thing.
but a lot of people would tell you not to use that
"You are stupid! You are stupid! Oh, and don't forget, you are STUPID!" - Dexter
Do you want to simply output the hex version to the screen? If so, you might be able to use:
float foo=4.5;
cout<<hex<<foo;
Not really sure though b/c I have never needed to output decimals in hex.
FillYourBrain, thanks for the help. Can you tell me how to convert this hex string back to an integer though? I looked up sprintf but i can't figure out how to convert back, and it seems to me that its not possible .
Oh yah, and is there a windows function to do this?
Last edited by pinkcheese; 08-11-2002 at 11:28 PM.
#include <iostream>
Do a google search to find a much more sophisticated Windows version, there are plenty! Some are quite complicated! (but allow for unicode and radix specification)Code:#include <stdlib.h> int main() { char in_buffer[50]; std::cout << "Enter a number: "; std::cin >> in_buffer; std::cout << std::endl; int some_int = atoi(in_buffer); char some_string[50]; itoa(some_int, some_string, 16); // converts some_int to null-terminated string with radix of 16 (hex) std::cout << "Hex: 0x0" << some_string << std::endl; itoa(some_int, some_string, 10); // converts some_int to null-terminated string with radix of 10 (dec) int back_to_int = atoi(some_string); std::cout << "Dec: " << back_to_int; return 0; }
>Can you tell me how to convert this hex string back to an integer though?
There's no need to convert it back if all you are doing is printing the values. The original integer should still be intact:
-PreludeCode:#include <cstdio> #include <iostream> int main() { int val = 0; char buffer[20]; std::cout<<"Enter a number: "; while ( std::cin>>val ) { sprintf ( buffer, "%#x", val ); std::cout<<"Your number was "<< val <<std::endl; std::cout<<"In hexadecimal "<< buffer <<std::endl; } return 0; }
My best code is written with the delete key.
on the other hand if you have a string input representing a hexidecimal number and you wish to convert it to decimal, then some additional work is necessary.
One way to accomplish conversion is as follows. First reverse the char in input by using strrev(). Then the index of the element is the power of 16. So if input is:Code:cout << "enter a hexadecimal value using standard notation" << endl; char input[80]; cin >> input; int decimal; cout << "hexadecimal input " << input << " in decimal form is " << decimal;
AB3
then reverse to get
3BA
and the decimal value is:
3*16^0 + B*16^1 + A*16^2 where A is decimal equivalent of 10 and B is decimal equivalent of 11, etc. In order to do this however you first need to convert each char in the string to an int and store it in an int array. Here's one way to do that part:
Code:int array[80]; char temp[3]; void convertHexCharToDecimalChar(char * input, int * array) { int i; for(i = 0; i < strlen(input); i++) { if(isdigit(input[i]) { temp[0] = input[i]; temp[1] = '\0'; array[i] = atoi(temp); temp[0] = '\0'; } else if(input[i] == 'A') { temp[0] = '1'; temp[1] = '0'; temp[2] = '\0'; array[i] = atoi(temp); temp[0] = '\0'; } else if(input[i] = 'B') { temp[0] = '1'; temp[1] = '1'; temp[2] = '\0'; // etc. } } int decimal = 0; for(i = 0; i < strlen(input); i++) { decimal += array[i]*pow(16, i); }
i actually had to write a program that had to convert to hex and back.
char sw(int num)
{
char h[16] = {'0','1','2','3','4','5','6','7','8','9','A','B',' C','D','E','F'};
return h[num];
}
void hex_help(long int num)
{
long int i, j, exp = 0, temp = num;
char hex[100];
while( temp >= 16)
{
exp++;
temp /= 16;
}
for ( i = 0; i <= exp; ++i)
{
temp = num;
for ( j = i; j <= exp; ++j)
{
if ( j == exp )
hex[i] = sw(temp % 16);
else
temp /= 16;
}
}
hex[exp + 1] = '\0';
cout << hex;
}
int pow(long int x, long int y)
{
long int i, pow = x;
if ( y > 1)
{
for (i = 0; i < y-1; ++i)
{
x *= pow;
}
return x;
}
if ( y == 0)
return 1;
if (y == 1)
return x;
}
void hex()
{
char h[20], a;
long int i, num = 0, len, j;
system("cls");
cout << "Enter hex (i.e. F8): ";
cin >> h;
len = strlen(h);
for (i = 0; i < len; ++i)
{
h[i] = (char) toupper(h[i]);
}
for (i = 0, j = len-1; i < len ; ++i, --j)
{
switch (h[i])
{
case '0': num += 0; break;
case '1': num += pow(16, j) * 1; break;
case '2': num += pow(16, j) * 2; break;
case '3': num += pow(16, j) * 3; break;
case '4': num += pow(16, j) * 4; break;
case '5': num += pow(16, j) * 5; break;
case '6': num += pow(16, j) * 6; break;
case '7': num += pow(16, j) * 7; break;
case '8': num += pow(16, j) * 8; break;
case '9': num += pow(16, j) * 9; break;
case 'A': num += pow(16, j) * 10; break;
case 'B': num += pow(16, j) * 11; break;
case 'C': num += pow(16, j) * 12; break;
case 'D': num += pow(16, j) * 13; break;
case 'E': num += pow(16, j) * 14; break;
case 'F': num += pow(16, j) * 15; break;
}
}
cout << "\n\n\n\tNumber is: " << num;
if (num < 256)
{
a = (char) num;
cout << "\n\n\tANSCII is: " << a;
}
cout << "\n\n\nPress 1 to do hex again, any other to return to menu\n>>>";
cin >> a;
if (a == '1')
hex();
}
yea but he wanted it converted to a string... ie: int 10 would become the string "0a"
to change to a string just call: hex_help(num)
oops... maybe I should have looked at the code first!