spot the error

I use the following to get two integers from user input, and also to check they are actually numbers...now it works fine if I enter an incorect number (say the first number) and asks me to re-enter, however if I enter an invalid number again then it goes into an eternal loop. But I cant spot the problem?

Any help or a solution would be much appreciated.

Code:

void userInput(char value[])
{
	int number1, number2;
	cout << "Please enter a number you wish to " << value << ":" << endl;
	cin >> number1;
	while (!cin >> number1)
	{
		cout << "Error! You have entered an invalid number, " << flush;
	// clear the state of cin, otherwise the while condition loops indefinently.
		cin.clear();
		cin.ignore(INT_MAX, '\n');
		cout << "Please re-enter a number:" << endl;
		cin >> number1;
	}
	cout << "Please enter a number you wish to " << value  << " " << number1 << " by" << endl;

	cin >> number2;

	while (!cin >> number2)
	{
		cout << "Error! You have entered an invalid number, " << flush;
		cin.clear();
		cin.ignore(INT_MAX, '\n');
			cout << "Please re-enter a number:" << endl;
		cin >> number2;
	}

PHP Code:

while (!cin >> number1) {

} 


Shouldn't it be

PHP Code:

while (!number1) {

} 


since you already got the value of number1 from the cin >> number1; above that.

Correct me if I'm wrong.

Your way seems to produce the same error too so there must be something wrong possibly elsewhere Ill keep looking in the code

If anyone is interested in the whole code (not that long).
a colour coded, spaced link is available here

cool ... do you own your own domain? How much did you pay for it?

Code:

int num1, num2;
int flag = 0;
while(flag == 0)
{
   cout  << "enter an integer value for num1" << endl;
   cin >> num1;
   if(cin.fail())
   {
      cout << "data entry error.  try again" << endl;
      cin.clear();
   }
  else
      flag == 100;
}

flag = 0;
//now repeat code for num2;