Quick Answer...

I have a pointer.... is there a way to chagne what data type it is?

Like i have 5 structures and i need to use the same variable but be able to switch betwen which type it is in the program. I dont really want to just cast it to another one cuz it get all bloated code. but can i just do someting to delete the current pointer and make it again w/ a different data type?

You could declare a void pointer and then make it point to the appropriate type.

I'm not exactly sure if this is what you want.
Eg.

Code:

typedef struct{/*...*/}ONE;
typedef struct{/*...*/}TWO;
typedef struct{/*...*/}THREE;
typedef struct{/*...*/}FOUR;
typedef struct{/*...*/}FIVE;

int main()
{
	void *ptr;
	ptr = new ONE;
	delete ptr;
	ptr = new TWO;
	delete ptr;
	ptr = new THREE;
	delete ptr;
	ptr = new FOUR;
	delete ptr;
	ptr = new FIVE;
	delete ptr;
	
	return 0;
}

You could always redefine the 5 structures as 5 classes that derive from a common base class. A pointer to a class can be assigned to derived classes as well.

Void pointers are handy for passing addresses, but you have to typecast them each time you use them.

OK, I understand your problem now.

If you used that method then you'd have to cast the pointer each time you used it.

Code:

int main()
{
	void *ptr;
	ptr = new ONE;
	((ONE*)ptr)->foo = NULL;
	delete ptr;
	return 0;
}

You could define a structure that had pointers to the other structures as members.

Code:

typedef struct{char* foo;}ONE;
typedef struct{char* foo;}TWO;
typedef struct{char* foo;}THREE;
typedef struct{char* foo;}FOUR;
typedef struct{char* foo;}FIVE;

typedef struct
{
	ONE* one;
	TWO* two;
	THREE* three;
	FOUR* four;
	FIVE* five;
}ALL;

int main()
{
	ALL* ptr = new ALL;
	
	ptr->one = new ONE;
	ptr->one->foo    = NULL;
                delete ptr->one;
                
	return 0;
}