i got a question about "cout"
Program 1:
#include <iostream.h>
int main()
{
char nx[]="hello";
cout << nx << "\n";
return 0;
}
Program 2:
#include <iostream.h>
int main()
{
int nx[]={1,2,3,4,5};
cout << nx << "\n";
return 0;
}
Why in program 1,the output result is "hello"
but program 2 output the memory address?
Let me try to answer, and if someone find this is wrong, please correct me.
In the first example, nx is a c string. Therefore when you cout nx, you'll see the string "hello". However, in the second example, nx is an array of integer. When you cout nx, it will print the address of that array, the address of nx[0].
Last edited by Unreg1stered; 07-20-2002 at 08:50 PM.
Blame C.
ostream has an overloaded operator the does special things with char*, for outputting C style strings.
ostream& operator << (char*)
While for any other type of pointer, it will simply print the memory address.
You can't cout integer arrays that way..
you have to insert the element number..
i.e. nx[1], nx[0], etc
MY HOMEPAGE www.akilla.tk
Thx for thr reply ^^
i got the problem solved
