fortran / c++ function arguments

Martijn · 07-09-2002

Hi there,

another question, i've to finish a fortran -> c++
conversion today and i have little programming
experience in both languages

. my question
about passing arguments is:
in fortran i can modify a local variable by calling
a function like this:

call derivs(xh,yt,dyt)
call derivs(xh,yt,dym)
call derivs(xh,yt,dyl)

in which the last argument is actually the
most wanted local output (return) variable. (it doesn't
have to be the same as in the function definition,
which can look like: subroutine derivs(a,b,c)).

how can i achieve this in c++? by this i mean
getting different return names from a
function call?

any help is greatly appreciated. o and monster
thanx for your answer to the last question ...

Martijn

**hk_mp5kpdw** · 07-09-2002

Code:

void func1()
{
    int local_var;       // Local integer variable
    local_var = 10;    // Initialize local_var to 10
    local_var = func2();  // local_var is now 20 instead of 10
}

int func2()  // func2 returns an integer argument to calling function
{
    return 20;  // Return the value 20 to the calling function
}

Is this what you are talking about or something else perhaps?

Martijn · 07-09-2002

thx! though i think i found what i was looking for:
i want to perform the same operation on different
arrays i think i should be working with pointers
as arguments. after running the code below
i think i understand how it works.

i read somewhere that FORTRAN works with
reference arguments to functions as a default,
while c++ works with values itself as defaults.

sorry the question above was a little confusing
to say the least

Greetz

____code_______________________

#include <iostream>
using namespace std;

void functest(int* a){
a[2]=8;}

int main () {
const int r=5;
int y[r];
int i=0, j;
y[0]=0;
while(i<5){
cout << i << "\t" << y[i] << "\n";
i++;
j=i-1;
y[i]=y[j]+10;
};
functest(y);
for(i=0;i<5;i++){
cout << "\n"<< i << "\t" << y[i];
}
return 0;
}

______________________________________________

**swoopy** · 07-09-2002

Code:

#include <iostream>
using namespace std;

void add(int a, int b, int &c);

int main(void)
{
   int a = 5;
   int b = 3;
   int c;

   add(a,b,c);
   cout << a << "+" << b << "=" << c << endl;

   return 0;
}

void add(int a, int b, int &c)
{
   c = a + b;
}

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