My book said array could only accept const argument, I tested it and found variable could also do. any ideas ?
this works pretty fine except the number are not what we expeted because of not be initialized.
PHP Code:#include <iostream>
void main()
{
int i;
int t=5;
int arr[t];
for(i=0; i<t; i++)
{
cout << arr[i] << endl;
}
}
Never end on learning~
Arrays need to know their size at compile time. There are numerous ways to get around it (resizing the arrays with dynamic memory, just using as big as you could ever need constant, using std::vector). For the time being, I'd recommend just using a large enough constant integer for the size. If you keep reading the book I am sure it will get into pointers, dynamic memory, and (hopefully, if it's a worthwhile book), get into the stl with the std::vector class.
I didnt reach those chapter now. I'll read more. thanx~Originally posted by SilentStrike
Arrays need to know their size at compile time. There are numerous ways to get around it (resizing the arrays with dynamic memory, just using as big as you could ever need constant, using std::vector). For the time being, I'd recommend just using a large enough constant integer for the size. If you keep reading the book I am sure it will get into pointers, dynamic memory, and (hopefully, if it's a worthwhile book), get into the stl with the std::vector class.
Never end on learning~
So.. maybe your code is working this time, but what in another one?
It is safer to use really constant size for an array(if you want an constant, not dynamic array), because your code maybe won't work with another compiler..
Well you can use the keyword new to dynamicaly allocate array space..
