Thread: function that takes struct?

Code:

#include <stdio.h>
#include <iostream.h>
#include<string.h>

struct myStruct{
int m;
int c;
};
void myFunc(myStruct &);    //prototype for function

int main(int argc, char *argv[])
{
myStruct s1;
myFunc(s1);                 //pass by refrence
cout<<"S1.m= "<<s1.m<<endl;
cout<<"S1.c= "<<s1.c<<endl;
cin>>"press enter";

  return 0;
}

void myFunc(myStruct & refStruct){
     refStruct.m=5;
     refStruct.c=10;
     return;
     }

hope i helped you

refStruct ----> is a reference (check up using references in any book or tutorial).........

I have to pass the structure as reference not by value from main to the fuction as passing by value will occure error coz the structure ll be out of scope (as the structure ll be local in the main)
so passing by reference (using the operator &) ll solve this problem .


sure you can use this way for any structure (give me exact problem , I ll show you how to solve it )

good luck

execuse me.........i cant get your point , u may clear urslef more , please

this is a complete chapter from "teach yourself c++"
about references, all u need about this topic ll be answered in this chapter.its very clear and full of examples, read it carefully, im ready to help u if u missunderstand anything within .......


alright??? good luck

Originally posted by pode
but i cant use this for any structure

No, you can't. Not for ANY structure at least.

You have to know what type of structure you are dealing with to be able to use it.

If you had declared an array of structures you wouldn't of needed to pass it by reference, as the address is automatically passed when dealing with arrays. Is this right?