Thread: hi, explanation for this.., using enum and the scope resolution..., ?

anyway this is what happened,

Code:

enum WHATSHAPE { TRIANGLE, SQUARE, CUBE };

class SHAPE
{
enum SHAPETYPE { DEFAULT, CUBE }m_ShapeType;
}

now i made a member function for the shape class, here is the definition

Code:

void CreateShape(WHATSHAPE shape)
{
     switch (shape)
     {
     case TRIANGLE:
          break;
     case SQUARE;
          break;
     case CUBE: // error, will say that cube is already used, ie it's value is 1;
         break;
 }

so the solution to that is, to make my case CUBE: like this instead,
case WHATSHAPE::CUBE, and this would work out well.,

and my question is this, how come this doesn't want to work?
case WHATSHAPE::SQUARE and case WHATSHAPE::TRIANGLE, i would have to modify my

enum SHAPETYPE and add these two constant value for that to work?


thanks a bunch!

switch (shape)
{
case TRIANGLE:
break;
case SQUARE;
break;
case CUBE: // error, will say that cube is already used, ie it's value is 1;
break;


look at the second case, that would be a : after SQUARE not a ;
changing that will probably fix your error

ei no, that's just a type,

Try
case WHATSHAPE::CUBE

or
case SHAPETYPE::CUBE

You have two CUBE's in scope, so decide which one you mean.

yes like i said that would work, but, what exacltydo you mean by,i have two cubes in scocpe? the other cube is decalred outside the class by using an enum, and the other one is declared inside the class?

and how come for the other 2 enums, i could'nt use the scope resolution on them? ie, WHATSHAPE::SQUARE // error, or WHATSHAPE::TRIANGLE // error troo,

many thanks,