problem with cin.getline()

my program compiles fine, but when i use cin.getline(); to get some data, i believe it reads the return from a previous cin so it blows through the code during runtime before i can even enter any information, i've put more cin's after the cin.getline, and they don't get skipped over, just the cin.getline();...here's the code, it's fairly short, can anyone help me with this bug?

Code:

#include <iostream>
#include <fstream>
#include <stdio>
using namespace std;

char id[500000];
char fileHandle[]=".txt";
char* fileName;
char input[100000];

int main() {

cout<<"PORTFOLIO EDITOR-FILE CREATION TEST"<<endl;
cout<<"Basically you type in the id number, it gets used in the creation of a file called that number plus .txt"<<endl;
cout<<"ENTER ID NUMBER"<<endl;
cin>>id;
cout<<"Now give me something to write into the file"<<endl;

cin.getline(input,99990,'\n');



fileName=strcat(id,fileHandle);
ofstream fout(fileName);
fout<<input;
fout.close();

return 0;
}

thanks

>>#include <stdio>
It's either stdio.h or cstdio, Edward knows of no other version.

Replace...
cin>>id;
with...
cin>>id, cin.get();
and it will work as expected.

=Ed=

thanks it worked, but uh...how do i get it to read after the first space? i know how to do it with the other method, but not with this...how would i go about it?

>>but uh...how do i get it to read after the first space?
Edward is slightly confused. Isn't that what getline is for in your code? Ed's solution was to use get after cin to remove the floating newline from the input stream so that getline would work right...

Code:

cin>>id, cin.get();
cout<<"Now give me something to write into the file"<<endl;

cin.getline(input,99990L,'\n');

=Ed=

ok, i got it, i thought that you meant to use that on the cin.getline(); , now i know what you mean....it's been a long couple of days so im not exactly on the top of my game. thanks for your trouble.

Hey, what I usually do in that case, is put a cin.ignore(); in right before the line it tends to skip. I don't know if that is good coding practice, lol. But it works.

The guy above me is right, if you put a cin.ignore before cin.getline it should work, like this.

Code:

#include <iostream>
#include <fstream>
#include <stdio>
using namespace std;

char id[500000];
char fileHandle[]=".txt";
char* fileName;
char input[100000];

int main() {

cout<<"PORTFOLIO EDITOR-FILE CREATION TEST"<<endl;
cout<<"Basically you type in the id number, it gets used in the creation of a file called that number plus .txt"<<endl;
cout<<"ENTER ID NUMBER"<<endl;
cin>>id;
cout<<"Now give me something to write into the file"<<endl;

cin.ignore();
cin.getline(input,99990,'\n');



fileName=strcat(id,fileHandle);
ofstream fout(fileName);
fout<<input;
fout.close();

return 0;
}

I haven't compiled it so let me know

much thanks to the both of you, both methods work...i also found another method i ended up using after i updated my program this morning, if you insert the cin.clear(); command after each cin, it clears in input buffer so that any extra returns still residing there will not affect the program. It works just like cin.ignore(); except you place it after the cin command.

Typically, you would use this function to clear any error bits set when there is an input error.

For example, you attempt to open a file that doesn't exist and wish to re-prompt the user for a valid file name. Wtihout using cin.clear();, the error bit will remain "set" and an attempt to re-input the file name will fail.

To my knowledge, cin.clear() does not substitute for cin.ignore().

You might want to try cin.flush() which flushes the buffer and inserts the '\n' char.

I've also found that cin.ignore(x, '\0') works well with menus where 'x' is a simple int value depending on your needs, i.e 2, 5, whatever. (The cursor displays next to your menu prompt as opposed to jumping down to the next line.)