Thread: Dynamic double array

Using pointers, how would you declare a dynamic double array to the effect of:

int matrix = new int[var][var];

where var is the size of the array.

??

It's quite similar to what you do to unidimensional arrays. But with a slight "problem":

Code:

int* matrix=0;
//.. get the dimension from user input or processing (dim1)
if(!(matrix = new int[dim1][const]))
   {
      cout << endl
           << "Memory allocation failed.";
      exit(1);               
   }

The problem as you can see is you can only specify the first dimension as a variable. All subsequent dimensions must be constants.

Also don't forget that no matter the number of dimensions, the delete statement only has one pair of square brackets:

delete [] matrix;

Yes... that was the problem I was facing. For anyone who's interested in the solution the answer is here:

http://www.cprogramming.com/cboard/s...c+double+array

He! I was finding it strange someone like you making such a simple question.
Sorry for misreading your question

No prob Mario, you helped me realize that conventional methods weren't going to work. My thanks.