For Advanced C++ Programmers only #2. "returning address of local variable"
Any idea why would this give me the following error:Code:inline void* GetArrayVariableFromType(void* data, size_t location, variabletype::e_type type) { switch (type) { case variabletype::_bool: { return &((std::vector<_bool>*)data)->operator[](location); } break; } return NULL; }
warning C4172: returning address of local variable or temporary
Do I really have to use std::_Vb_reference?
I just found out std::vector<int> returns int& for operator[]
std::vector<bool> returns std::_Vb_reference.
Weird...
Found out std::vector<bool> packs data into 1 bit, preventing me from pointing a boolean to its data. The workaround is to use std::vector<char> instead of std::vector<bool>.
Fixed.
I suppose it's debatable, but this seems more robust anyway. No reason to stop using vector<bool> because of bit-packing.Code:template<typename T> inline T GetArrayVariableFromType(vector<T> &data, size_t location, variabletype::e_type type) { switch(type) { case variabletype::_bool: return data[location]; default: throw runtime_error(__func__ /* C++11 */ ); } return T(); // appease the compiler }
Last edited by whiteflags; 07-23-2016 at 10:21 PM.
