how do i display this struct i have??

i want to be able to display wut i input in the struct. heres the code:

Code:

---

struct agendaview
{
        char name[15];
        char tel [10];
        char adress[50];
};
//this is the struct code

void newperson ()
{
        agendaview *newperson ;
        newperson = new agendaview ;
        if (newperson != NULL )
        {
                cout<<"Name:";
                cin.get (newperson->name[15]);
                cin.ignore (80,'\n');
                cout<<"TEL:";
                cin.get (newperson->tel[10]);
                cin.ignore (80,'\n');
                cout<<"Adress:";
                cin.get (newperson->adress[50]);
                cin.ignore (80,'\n');
        }

}
//this is how i enter the data.

---

now i need to know how do i display the data i input.
something like this:

name tel adress
------------------------------------------------------------------------------
(wutever) (wutever) (wutever)

thx in advance.

Why dont you use cout << agendaview.name and so on

change this:

cin.get (newperson->name[15]);

to this:

cin.getline(newperson->name, 15);

and so on.

to display just go

cout << newperson->name << ' ' << newperson->tel etc.

cout <<agendaview.name did not work.
so i used the other advice which works except for one thing. i need to initialize newperson to something. i really dont know wut to initialize it to.

Code:

---

void viewall ()
{
        agendaview *newperson;
        // i need to initialize newperson to something here
                cout <<newperson->name<<'  ';
        cout <<newperson->tel<< '  ';
        cout <<newperson->adress<<endl;
}

---

You are writing C++ in C!!

...and I forgot to use code tags!

Here:

Code:

---



class agendaview { public:
char name[15];       
char tel [10];       
char adress[50];


agendaview( char *Name, char *Tel, char *Address)
{
strncpy(name, Name, 15);
strncpy(tel, Tel, 10);
strncpy(adress, Address, 15);
}

void create(){       
cout<<"Name:";
cin.get (name, 15);               
cin.ignore (80,'\n');               
cout<<"TEL:";               
cin.get (tel, 10);
cin.ignore (80,'\n');               
cout<<"Adress:";               
cin.get (adress, 50);               
cin.ignore (80,'\n');       
}

void print() {
cout<<"Name:";
cout<<name;
cout<<"TEL:";               
cout<<tel;
cout<<"Adress:";               
cout<<adress;
}

};



int main()
{

agendaview Ralph("Ralph", "2146162352", "5720 maple Ave");

agendaview New;

New.create();

Ralph.print();

New.print();


return 0;
}

---

you could use linked lists for your agenda, i think that would be ezier to make a function to view it then using just structs.

PHP Code:

---

typedef _agenda struct
{
   char name[15];    
   char tel [10];    
   char address[50];

   _agenda  *next;
} agenda;

agenda *root;
root->next = NULL; 


---

or whatever for the linked list (im not that good at linked lists right now)

PHP Code:

---

void view_agenda()
{
   agenda *temp;
   *temp = new agenda;

   temp = root; // considering root is the first node in your linked list
   
   while(temp->next != NULL)
   {
      cout << temp->name << ' ';
      cout << temp->tel << ' ';
      cout << temp->address << endl;

      if(temp->next != NULL)
         temp = temp->next;
   }
} 


---

then to add a new person do something like:

PHP Code:

---

void AddPerson(char name[15], char tel[10], char address[50])
{
   agenda *temp;
   agenda *newperson;

   temp = new agenda;
   newperson = new agenda;

   while(temp->next != NULL)
   {
      if(temp->next != NULL)
         temp = temp->next
   }

   newperson = temp; // Set newperson to the last position in the linked list

   delete temp; // delete temp from the memory

   // Add all the details for the new person
   newperson->name = name;
   newperson->tel = tel;
   newperson->address = address;
   newperson->next = NULL;
} 


---

well, something like that, as i said im not that great with linked lists

This is a C style struct

typedef struct agendaview

This is a C++ style struct

struct agendaview

Use the latter in C++ code.
__________________________________
agendaview *newperson;
// i need to initialize newperson to something here

you did a pretty decent job of initializing a pointer with data in newperson(), so I know you know how to do it at leasty one way. Maybe if you give a description of you what you are trying to do in the overall program we can answer you question better. If you are trying to display nodes in a list, the OkieSmokie has some pretty good ideas, not perfect mind you, but pretty good nevertheless.
________________________________________

try not to use the same name for a variable and a function. It can get confusing: see newperson() and agendaview * newperson;