I need help!!!!!

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  1. #1
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    I need help!!!!!

    I have to enter a three digit number and then get an output of
    the first digit
    the second digit
    the third digit

    ~Sam Mixter~

  2. #2
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    Please post your code. Its not easy to guess what's going on.

  3. #3
    Refugee face_master's Avatar
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    use an array

  4. #4
    Refugee face_master's Avatar
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    if you don't know how to do an array, here is a liitle bit of code...
    Code:
    #include <iostream.h>
    #include <stdlib.h>
    
    int main()
    {
    int array[2]; // remember that C++ regards 0 as one of the parts of the array
    cout << "Enter your 3 digit number: ";
    cin >> array[2];
    cout << "\n";
    cout << array[0];
    cout <<"\n";
    cout << array[1];
    cout << "\n";
    cout << array[2];
    
    system("pause"); // system calls are crap, I know
    return 0;
    }
    hope this helps

  5. #5
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    Hi

    just few remarks about the code above:

    int array[2]; -
    declare an array with only 2 elements of type int
    they can be accessed via indexes 0 and 1 so the last cout with array[3] is illegal, it will print a garbage.

    cin >> array[2]; -
    is it supposed to read several int's from the cin? if true - then you are in trouble.
    this expression just read one integer value from the keyboard and places it in an unexisting place - array[2];

    so to correct the code above - enlarge the array ehough to hold all the three elements and read them one by one.

    damyan

  6. #6
    Refugee face_master's Avatar
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    in this little code, when it inputs array[2], it gets all three numbers. eg. if you enter 111, it will output:
    1
    1
    1
    but if you input 1111 it will output a whole lot of garbage. In other words: it works, end of story.

  7. #7
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    Hi face_master,

    :-) did you ever try this code, so becouse you didn't
    just for example

    let declare an variable of the same type as the elements of the array - int - just before the declaration of the array[2]

    ....
    int foo = 5;
    int array[2];
    ...
    and output that variable - foo - after your
    cin >> array[2];
    cout << foo;

    these are all local variables allocated in the stack
    when you modify an unallocated variable - in our case array[2]
    you change the memory just above the array elements - the variable declared just before the array or if such variable didn't exist you override the return addres of the function and it will not exit normally.

    damyan

  8. #8
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    Damyan is right on declaring arrays. Declaring
    int array[2]; will declare a 2 element array, with values array[0] and array[1].
    As for inputting cin >> array[2] to input the entire number into each array element, maybe, but I've never seen that. You usually use a loop to input multiple values. cin >> array[2] would input only into the specific variable array[2], which in this case doesn't exist. It may be compiler dependent, but this will give out of bounds errors in msvc.

  9. #9
    zen
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    If this is a homework question then you may not be able to use an array. Check this post for details on how to split the number up.

  10. #10
    Registered User WayTooHigh's Avatar
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    i'd write this program like this:
    Code:
    #include<iostream.h>
    #include<stdio.h>
    
    int main()
    {
    	int x;
    	char y[2];
    
    	cout<<"Enter a three digit number\n";
    	cin>>x;
    	cout<<"\n";
    	sprintf(y, "%i", x);
    	cout<<y[0]<<"\n";
    	cout<<y[1]<<"\n";
    	cout<<y[2]<<"\n";
    
    	return 0;
    }
    is this right? or is there some reason i shouldn't do this?
    Sometimes, the farthest point from the center is the center itself.

    Your life is your canvas, it's only as beautiful as you paint it.

  11. #11
    zen
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    is this right?
    Probably (if you add an extra charater to the array), but you can do it without the function call and array -

    #include <iostream>

    using namespace std;

    int main()
    {
    int a;
    cout << "Enter 3 digit number: ";
    cin>>a;

    for(int i=100;i>0;i/=10)
    {
    cout <<a/i << " ";
    a%=i;
    }

    return 0;
    }

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