hello everybody,
here i've one problem .can u guys please tell me what is output and *why?
main()
{
unsigned int i=10;
while(i>=0)
{
printf("%u\n",i);
i--;
}
}
thank u
srinu
with regards
c/c++ prpgramming
hello everybody,
here i've one problem .can u guys please tell me what is output and *why?
main()
{
unsigned int i=10;
while(i>=0)
{
printf("%u\n",i);
i--;
}
}
thank u
srinu
with regards
srinu
unsigned int always >= 0
So you get infinite loop.
change to signed int or modify your while ( condition )
I don't know how 0 is dealt with with respect to being signed or unsigned, but I would expect it to be a valid value for an unsigned int. IF it isn't, then you will get a never ending loop.
Otherwise the loop counts down from 10 to 0 inclusive by one stopping when i = -1, placing each new numeral on a new line using C style output.
As already said I believe, unsigned int i is always greater than or equal to 0, hence the infinite loop. The above is the first few lines of output.Code:10 9 8 7 6 5 4 3 2 1 0 4294967295 4294967294 4294967293 4294967292
When all else fails, read the instructions.
If you're posting code, use code tags: [code] /* insert code here */ [/code]
dope slap to forehead.
