c/c++ prpgramming

This is a discussion on c/c++ prpgramming within the C++ Programming forums, part of the General Programming Boards category; hello everybody, here i've one problem .can u guys please tell me what is output and *why? main() { unsigned ...

  1. #1
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    Lightbulb c/c++ prpgramming

    hello everybody,
    here i've one problem .can u guys please tell me what is output and *why?
    main()
    {
    unsigned int i=10;
    while(i>=0)
    {
    printf("%u\n",i);
    i--;
    }
    }

    thank u
    srinu
    with regards
    srinu

  2. #2
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    unsigned int always >= 0
    So you get infinite loop.

    change to signed int or modify your while ( condition )

  3. #3
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    I don't know how 0 is dealt with with respect to being signed or unsigned, but I would expect it to be a valid value for an unsigned int. IF it isn't, then you will get a never ending loop.

    Otherwise the loop counts down from 10 to 0 inclusive by one stopping when i = -1, placing each new numeral on a new line using C style output.

  4. #4
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    Code:
    10
    9
    8
    7
    6
    5
    4
    3
    2
    1
    0
    4294967295
    4294967294
    4294967293
    4294967292
    As already said I believe, unsigned int i is always greater than or equal to 0, hence the infinite loop. The above is the first few lines of output.
    When all else fails, read the instructions.
    If you're posting code, use code tags: [code] /* insert code here */ [/code]

  5. #5
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    dope slap to forehead.

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