integer strangeness

I have an integer declared in a struct (player.gold) everything is fine and dandy until the integer reaches 100. Upon reaching that dreadfull number it starts displaying as 1,00. and when I save the number to a text file it saves the same way 1,00 (although when stepping through the program it says its 100). I use plain old couts. Does anyone have a clue why it does this?

Sounds weird, can you post some code?

yeah I found the exact place where it starts happening in my program. here is the code : (in runable form ) !beware messy code!

Code:

#include <iostream.h>
#include <conio.h>
#include <string.h>

const string SKILL_LIST ="Bladecraft,Knife";

int main()
{
  string req[5];
  string temp;
  for (int a=0;a<5;a++)
    req[a]="\0";
  int x=0;
  int pager=0;
  int y=0;

  clrscr();

  cout << 100 <<endl;

  do
  {
    cout << 100 <<endl;
    while((SKILL_LIST[x+pager]!=',')&&
          (SKILL_LIST[x+pager]!='\0'))
    {
      temp[x]=SKILL_LIST[x+pager];
      x++;
      cout << 100 <<' ';
    }
    cout <<'\n';
    if (SKILL_LIST[x+pager]==',')
      {
        cout << 100 <<' ';
        x++;
        pager=x;
        x=0;
        while (x<pager)
        {
          cout << 100 <<' ';
          req[y]=req[y]+temp[x];
          x++;
        }
        cout <<'\n';
        req[y]=req[y]+'\0';
        temp=req[y];
        req[y]=temp;
        x=0;
        y++;
        temp[0]='\0';
      }
    else
    {
      cout << 100 <<' ';
      int a =0;
      int trash=pager+x;
      while (trash>pager)
      {
        cout << 100 <<' ';
        req[y]=req[y]+temp[a];
        pager++;
        a++;
      }
      cout <<'\n';
      req[y]=req[y]+"\0";
    }
  }while (SKILL_LIST[x+pager]!='\0');
  cout << 100;
  getchar();
  return 0;
}//end main

The code works exactly the way it should ie
req[0]=Bladecraft
req[1]=Knife

was going to change this code to something else but now i'm curious as to why it does this...

the cout's were added to show the output

I'm surprised this compiles. 100 is not the name of a variable nor is it a literal string so I would have expected the compiler to indicate error on this line(s):

cout << 100 <<' ';

It is literal it is a literal integer...

Originally posted by elad
I'm surprised this compiles. 100 is not the name of a variable nor is it a literal string so I would have expected the compiler to indicate error on this line(s):

cout << 100 <<' ';

You can print integer numbers. But I can't understand why cout << 100 would print 1,00... Bad compiler???

btw I do have this code fixed (and much shorter) using strtok() but now I'm wondering (still) why this does this is it an error in my messy code? (although it works) bad compiler? (borland builder 5.0) or something else...