Hi,
If a variable has to be declared before use, then why the following code works? Since in the class definition x is declared after its use in f().
Thanks in advance.Code:#include <iostream>using namespace std; class A { public: int f() { return x; } int x = 10; }; int main() { A a; cout << a.f() << endl; return 0; }
O_oIf a variable has to be declared before use, then why the following code works? Since in the class definition x is declared after its use in f().
Though greatly simplified, you may think of this as the compiler being required to parse (read) the definition of a class before parsing the definition of function defined within the class definition.
The behavior is required otherwise the member function `Class Class::Whatever();' could not return a `Class' instance for not knowing enough about `Class' at that point.
Unfortunately, when you start reaching for templates and `typedef' things get complicated and not all compilers are good enough to smooth out the wrinkles. You are better off developing a habit of defining things before you use them even within classes, but you don't have to... until you do I guess.
Soma
“Salem Was Wrong!” -- Pedant Necromancer
“Four isn't random!” -- Gibbering Mouther
