Hi,
I have a problem.. I need your sugestion.
I am doing a editor program in c++ where i need to accept huge strings.. Some times 3600 chars long.. the problem is how do i do it... If i use cin or getline etc etc it can accept only limited amount of characters around 126 i guess.... After that it does not accepts any chars from the user and beeps when the keys are pressed... So how do i accept a string this big...
Thanx
Vasanth
Read a block of characters with getline, if that block does not contain a newline character then keep reading blocks until it does. Just keep placing the blocks in the same array until you hit the newline and you'll have one very long string.
-Prelude
My best code is written with the delete key.
can you please elobrate it.....
Here's the basic idea, sorry about the ugly code:
-PreludeCode:#include <stdio.h> #include <string.h> int main ( void ) { int i = 0; char buffer[1000] = {'\0'}, temp[20] = {'\0'}, *p; while ( ( p = strchr ( buffer, '\n' ) ) == NULL && i < 1000 ) { fgets ( temp, sizeof temp, stdin ); strcat ( buffer, temp ); i += strlen ( temp ); } puts ( buffer ); return 0; }
My best code is written with the delete key.
No that did not work... I have attached my c++ source file.. It accepts input from user.. Try making it accept more than 200 characters... (2 lines of data) ....
If you solve it please post it here...
thanx
vasanth
Buffer will contain every char except EOF in filename if less thanCode:ifstream fin("filename"); char ch; int index; const int MAX = 35001;//hold string with up to 35,000 char char * buffer = new char[MAX]; if(MAX != NULL) { for(index = 0; index < MAX - 1; index++) { buffer[index] = '\0'; } while(fin.get(ch) != EOF && index < MAX - 1) { buffer[index] = ch; } cout << buffer; }
35,001 char in file
You may need to jiggle the while conditional a little. I forget whether EOF is compatible with char type or not.
oops, should have been if(buffer != NULL){
sorry
also you need to reset index to 0 after using it in the for loop and before using in the while loop.
