Thread: C++11 for statement and addresses:

Why is C++11 act different than C++ in reference to the for statements.

I was pretty excited when I read how they worked in my textbook and now I am left with questions. Why am I getting different addresses?

Code:

 #include <iostream>
#include <array>

using namespace std;

void changePointer(int change[])
{
        cout<<change<<endl;
}

int main(int argc, const char * argv[])
{

    array <int, 5> drew={34,22,55,56,98};
    
    for(int items : drew)
        cout<<"The arrays is:"<<items<<endl;
        
    for (int change : drew) {
        cout<<"The address is:"<<&change<<endl;   //c++11 is suppose to do the same as below
    }
    
    for (int i=0; i<5; i++) {
        
    changePointer(&drew[i]);     // this did what I thought it would
        
    }
    
    return 0;
}

I think it might be because using int[] tells your compiler or w/e to make a static copy of whatever you're passing to it. You're passing the value of an address and where that value is stored is what you're printing, right?

Is that right? I'm probably wrong but I figured, eh, the internet, right?

What if you printed changed[0]?

Your amazing!!!!

Hopefully one day I understand programing like you laser light !!!

If I change the value at the location of the variable, I change it everywhere right. Thus it should print it out whenever I output it after I changed it. What am I missing? I thought I did this below.

Code:

 #include <iostream>
#include <array>

using namespace std;

int changer(int *a)
{
    return *a * 4;

}



int main(int argc, const char * argv[])
{

    array <int, 5> drew={34,22,55,56,98};
    
    for(int items : drew)
        cout<<"The arrays is:"<<items<<endl;
        
    for (int& change : drew) {
        cout<<"The address is:"<<&change<<endl;   
    }
    
    
    for(int &i : *&drew)            //pass a copy and did simple arithmetic
        
        cout<< i*6 <<endl;
    
    cout<<changer(&drew[0])<<endl;              // changed the value with a pointer
    
    for(int items : drew)
        cout<<"The arrays is now:"<<items<<endl;      // Here the value should be the same as above
    
    return 0;
}

> *a * 4;

This is not an assignment. You need to store the result, for example:

*a *= 4;

ahhhh... Thanks... Finally I get pointers and pass by reference. It's lovely how programing can make you feel like a complete retard at times.