can someone explain to me what Org is in this code dealing with operator functions

**c++noob145** · 04-03-2013

Code:

ostream &

Code:

operator<<(ostream& output, Bank_Acct & Org)

Code:

{
      output<<endl<<"Name "<<Org.name;
      output<<endl<<"The balance is "<<Org.balance<<endl;
returnoutput;
}

I'm learning about operator overloading and I'm confused where Org came from

I'm guessing it just a placeholder name like when you create functions like

Code:

void Add(int &a, int &b){
    a+=1;
    b+=1;
}

and when you call the function

in main

like this

Code:

int main(){

         int s=4;
         int g=5;
         Add(s,b);


}

so the variables don't nessarily have the same name.

**laserlight** · 04-03-2013

Yes, it is just a parameter name.

**c++noob145** · 04-03-2013

and Org is just the actual class object that is being passed through as a reference?

**laserlight** · 04-03-2013

Originally Posted by c++noob145

and Org is just the actual class object that is being passed through as a reference?

No, it is the parameter (also known as the formal parameter or formal argument), which is of type reference to Bank_Acct. This is the same as if the operator<< were say, a function named "foo". It so happens that this function has a more... interesting name.

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