How to overload a class func with an outside func while in a the same class

This is a discussion on How to overload a class func with an outside func while in a the same class within the C++ Programming forums, part of the General Programming Boards category; I have a class that has a method name the same as another method separate from the class and I ...

  1. #1
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    How to overload a class func with an outside func while in a the same class

    I have a class that has a method name the same as another method separate from the class and I am writing another class method in the class but want to call the outside method instead of the one in the class.

    Is there a way I can overload the class method with the outside one?

    Here is what the situation looks like
    Code:
    class LongInt
    {
         int digits() { /* find total # of digits of this object */
         LongInt divide(const LongInt&); // this method is where I want to use the outside digits(int number) method 
    }
    int digits(int number){ /*finds total digits of number */}
    The problem is when I call digits(number) inside the class, I get compiler error saying it doesn't take 1 arguments.

  2. #2
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    hmm, when I think about it more, what I'm trying to do seems like bad programming practice.

  3. #3
    Cat
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    It's not really 'overriding' - you can certainly call a function by fully qualifying it. If it's in a namespace, it would be namespace::function(), or in the global namespace it would be ::function().

    You are right, though, this might not pass the smell test - I'm glad you're cultivating that nagging feeling that there might be a better way - that is too rare of a skill sadly
    You ever try a pink golf ball, Wally? Why, the wind shear on a pink ball alone can take the head clean off a 90 pound midget at 300 yards.

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    Quote Originally Posted by workisnotfun View Post
    The problem is when I call digits(number) inside the class, I get compiler error saying it doesn't take 1 arguments.
    As to explaining that .... within a class member function, the attempt to use the name digits matches LongInt's digits() function first. This is called name hiding in some circles: the name LongInt::digits hides ::digits within context of the LongInt class. That's as far as the compiler goes: it matches the name digits, detects that LongInts::digits() accepts no arguments, and complains about a mismatch since you supplied an argument. The compiler does not (and the standard actually requires that it does not) attempt to match something else visible named digits that accepts a single argument. Hence the need for using the scoping operator, as mentioned by Cat.
    Right 98% of the time, and don't care about the other 3%.

    If I seem grumpy or unhelpful in reply to you, or tell you you need to demonstrate more effort before you can expect help, it is likely you deserve it. Suck it up, Buttercup, and read this, this, and this before posting again.

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