Thread: Entering valid user input?

Hello guys; I am wondering if you can help me.
How can I write my simple program so if the user enters an invalid number,
The program won’t exit? I know I am supposed to use a if (cin) or if (!cin),
But I don’t know where in the program or how I should use it. Right now my
Program looks kind of like this:
If (number > 1 && number < 1001)
Go through some function loops
Else
Cout << “invalid number”;
I need to write it so when the user enters an invalid number, the program
Would Keep asking for the right number until it's given.
Thanks guys.

Like so.

Code:

#include <iostream>
#include <iomanip>
#include <limits>
using namespace std;

int main()
{
  int var = 0;
  do {
    if ( cin >> var ) {
      if ( var >= 1 && var <= 99 ) {
        cout << "Good" << endl;
      } else if ( var != -1 ) {
        cout << "Out of range" << endl;
      }
    } else {
      cout << "Garbage input" << endl;
      cin.clear();
      cin.ignore(numeric_limits<streamsize>::max(),'\n');
    }
  } while ( var != -1 );
}