Change one element of string pointed by char pointer

**std10093** · 02-15-2013

1-I really did not understand, otherwise no need to ask you to rephrase.

2-Much better now. I am going to upload this too.

3-Well, as you can see in the link in my previous post, I gave them to you, but if you do not like this, I can remove it.

4-I am not saying that my posts are perfectly stated, so it's ok to be rephrased. The paradigms where there to demonstrate what you can and can not do. I know enough people that would try to do what you can't do. So, I write this code, in order to "prove" that you can't do them

Anyway, thanks for being pedantic

**C_ntua** · 02-15-2013

Originally Posted by whiteflags

A string literal is actually "This" or "this" -- objects of type char[5] -- the data proper

My turn to rephrase! "The string literal is of type const char[5]". The reason it works for an array is just because even if the syntax is similar it means something completely different. One is

Code:

//char* p = "hey";
const char temp[] = {'h','e','y','/0'};
char* p = temp; //should really be const char*

the other

Code:

//char a[] = "hey";
char a[] = {'h','e','y','\0'};

Thread: Change one element of string pointed by char pointer

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