Problem with looping

Hello I'm currently creating a guessing game program where the user will be asked to guess the computer generated number. Once the program is finished, at the end the user will be asked if they want to play again. If the user types "Y or Y" the program will loop and when the user types "n or N" it will not loop. Check out my code below.

Code:

#include<iostream.h>#include<stdio.h>
#include<dos.h>
#include<stdlib.h>
#include<conio.h>
#define g gotoxy


void main(){
int a,l,b,guess,row,col,answer,num,clue=5;
textcolor(YELLOW);
clrscr();
randomize();
a=random(30)+1;
b=random(100)+20;
num=random(a)+b;
clrscr();
for(col=1;col<=79;col++)
{
g(col,19);
cout<<"Í";
g(col,21);
cout<<"Í";
}
for(row=1;row<=50;row++)
{
g(1,20);
cout<<"º";
g(79,20);
cout<<"º";
}
for(col=1;col<=77;col++)
{
g(2,18);
cout<<"Wait while the game is loading..."<<endl;
g(col+1,20);
cout<<">";
delay(100);
}
do{
clrscr();
g(15,15);
cout<<"Guess the number!";
g(15,17);
cout<<"Clue: The number is between:\t"<<a <<"\tand\t" <<b+a;
g(15,19);
cout<<"Remaining number of trials:\t"<<clue;
textcolor(GREEN);
if((guess<num))
cout<<"\n\nEnter higher!";
if((guess>num)&&(clue<5))
cout<<"\n\nEnter lower!";
g(17,22);
cout<<"\nYour estimate is:";
cin>>guess;
if(guess!=num)
textcolor(CYAN);
clue--;
if(guess==num)
{
textcolor(MAGENTA);
clue=0;
l=1;
cout<<"Wow! You're right! The number is\t" << num;
}
}while(clue!=0);
if(l==0)
cout<<"\nSorry,you failed to guess the number, the number is\t" << num;
cout<<"\n---------------------------------------------------------";
cout<<"\n\tWould you like to play again?[Y/N]";
cin>>answer;
if((answer='N')||(answer='n'))
clrscr();
textcolor(GREEN);
cout<<"\n\n\n\n\t\tYou have chosen to quit. Thanks for playing!"<<endl;
getch();
}

I can't loop this program please help me with it. Thanks in advance!

Your code is unreadable - SourceForge.net: Indentation - cpwiki
Fix the indentation.

> #define g gotoxy
Don't do this.
Write it out properly.

oh my mistake, here is the code:

Code:

#include<iostream.h>
#include<stdio.h>
#include<dos.h>
#include<stdlib.h>
#include<conio.h>
#define g gotoxy


void main(){
int a,l,b,guess,row,col,answer,num,clue=5;
textcolor(YELLOW);
clrscr();
randomize();
a=random(30)+1;
b=random(100)+20;
num=random(a)+b;
clrscr();
for(col=1;col<=79;col++)
{
g(col,19);
cout<<"Í";
g(col,21);
cout<<"Í";
}
for(row=1;row<=50;row++)
{
g(1,20);
cout<<"º";
g(79,20);
cout<<"º";
}
for(col=1;col<=77;col++)
{
g(2,18);
cout<<"Wait while the game is loading..."<<endl;
g(col+1,20);
cout<<">";
delay(100);
}
do{
clrscr();
g(15,15);
cout<<"Guess the number!";
g(15,17);
cout<<"Clue: The number is between:\t"<<a <<"\tand\t" <<b+a;
g(15,19);
cout<<"Remaining number of trials:\t"<<clue;
textcolor(GREEN);
if((guess<num))
cout<<"\n\nEnter higher!";
if((guess>num)&&(clue<5))
cout<<"\n\nEnter lower!";
g(17,22);
cout<<"\nYour estimate is:";
cin>>guess;
if(guess!=num)
textcolor(CYAN);
clue--;
if(guess==num)
{
textcolor(MAGENTA);
clue=0;
l=1;
cout<<"Wow! You're right! The number is\t" << num;
}
}while(clue!=0);
if(l==0)
cout<<"\nSorry,you failed to guess the number, the number is\t" << num;
cout<<"\n---------------------------------------------------------";
cout<<"\n\tWould you like to play again?[Y/N]";
cin>>answer;
if((answer='N')||(answer='n'))
clrscr();
textcolor(GREEN);
cout<<"\n\n\n\n\t\tYou have chosen to quit. Thanks for playing!"<<endl;
getch();
}

Focus first on Salem's post.

Actually I can't tell what of what he said did you actually followed.

For example, this code is not good in terms of indentation

Code:

if(3==4)
{
cout<<"What?"<<endl;
}

A better indentation would produce something like this

Code:

if(3==4)
{
     cout << "What?" << endl;
}

Then read, what Salem said said about the define you use.

Finally, focus on his picture.
You should have

Code:

int main()
{
   /* your program*/
   return 0;
}

rather than

Code:

void main()
..

And something from me (line 72)

Code:

if((answer='N')||(answer='n'))
clrscr();

You probably want to use the equality sign, which is == . One equal sign, means assignment.

Nothing more from me, until you follow Salem's post

Code:

#include<iostream.h>
#include<stdio.h>
#include<dos.h>
#include<stdlib.h>
#include<conio.h>


int main(){
int a , l , b , guess , row , col , answer , num , clue = 5;


	textcolor(YELLOW);
	clrscr();
	randomize();
	a = random(30) + 1;
	b = random(100) + 20;
	num = random(a) + b;
	clrscr();


for(col = 1; col <= 79 ; col++)
{
	gotoxy(col, 19);
	cout << "Í";
	gotoxy(col, 21);
	cout << "Í";
}


for(row = 1; row <= 50; row++)
{
	gotoxy(1, 20);
	cout << "º";
	gotoxy(79, 20);
	cout << "º";
}


for(col = 1; col <= 77; col++)
{
	gotoxy(2, 18);
	cout << "Wait while the game is loading..." <<endl;
	gotoxy(col + 1, 20);
	cout << ">" ;
	delay(100);
}


do{
	clrscr();
	gotoxy(15 , 15);
	cout << "Guess the number!" ;
	gotoxy(15 , 17);
	cout << "Clue: The number is between:\t" << a << "\t and \t" << b + a;
	gotoxy(15 , 19);
	cout << "Remaining number of trials: \t" << clue;
	textcolor(GREEN);


		if((guess < num))
			cout << "\n\n Enter higher!";
		if((guess > num)&&(clue < 5))
			cout << "\n\n Enter lower!";
			gotoxy(17, 22);
			cout << "\n Your estimate is:";
			cin >> guess;
		if(guess!= num)
			textcolor(CYAN);
			clue--;
		if(guess == num)
			{
				textcolor(MAGENTA);
				clue = 0;
				l = 1;
				cout << "Wow! You're right! The number is\t" << num;
			}
			
}while(clue!= 0);
if(l == 0)
	cout <<"\nSorry,you failed to guess the number, the number is\t" << num;
	cout <<"\n---------------------------------------------------------";
	cout <<"\n\tWould you like to play again?[Y/N]";
	cin >> answer;
if((answer == 'N')||(answer == 'n'))
	clrscr();
	textcolor(GREEN);
	cout<< "\n\n\n\n\t\tYou have chosen to quit. Thanks for playing!" << endl;
return 0;
}

There you go sir. I'm sorry about the indention thing, I'm completely a newbie with this thing. I tried to run this new code but it still doesn't loops

Good job about indentation. Thank you

Which loop is not working?

In this part of your code

Code:

if((guess < num))
            cout << "\n\n Enter higher!";
        if((guess > num)&&(clue < 5))
            cout << "\n\n Enter lower!";
            gotoxy(17, 22);
            cout << "\n Your estimate is:";
            cin >> guess;
        if(guess!= num)
            textcolor(CYAN);
            clue--;
        if(guess == num)
            {
                textcolor(MAGENTA);
                clue = 0;
                l = 1;
                cout << "Wow! You're right! The number is\t" << num;
            }

are you sure about the brackets? When there are no brackets below an if statement, then the body of the if, is considered to be only the very next line of code.
So, your code is equivalent to this

Code:

        if((guess < num))
        {
            cout << "\n\n Enter higher!";
        }
        if((guess > num)&&(clue < 5))
        {
            cout << "\n\n Enter lower!";
        }
            gotoxy(17, 22);
            cout << "\n Your estimate is:";
            cin >> guess; 
        if(guess!= num)
        {
            textcolor(CYAN);
         }
            clue--;
        if(guess == num)
            {
                textcolor(MAGENTA);
                clue = 0;
                l = 1;
                cout << "Wow! You're right! The number is\t" << num;
            }

I would suggest to always use brackets (when you are in your first steps ).
So, you might want to place some brackets in other positions, judging from your indentation.

// no need to call me sir

Code:

#include<iostream.h>
#include<stdio.h>
#include<dos.h>
#include<stdlib.h>
#include<conio.h>


int main(){
int a , l , b , guess , row , col , answer , num , clue = 5;


	textcolor(YELLOW);
	clrscr();
	randomize();
	a = random(30) + 1;
	b = random(100) + 20;
	num = random(a)+b;
	clrscr();


for(col = 1; col <= 79 ; col++)
{
	gotoxy(col, 19);
	cout << "Í";
	gotoxy(col, 21);
	cout << "Í";
}


for(row = 1; row <= 50; row++)
{
	gotoxy(1, 20);
	cout << "º";
	gotoxy(79, 20);
	cout << "º";
}


for(col = 1; col <= 77; col++)
{
	gotoxy(2, 18);
	cout << "Wait while the game is loading..." <<endl;
	gotoxy(col+1,20);
	cout << ">";
	delay(100);
}


do{
	clrscr();
	gotoxy(15, 15);
	cout << "Guess the number!" ;
	gotoxy(15, 17);
	cout << "Clue: The number is between:\t" << a << "\tand\t" << b+a;
	gotoxy(15, 19);
	cout << "Remaining number of trials:\t" << clue;
	textcolor(GREEN);


		if((guess < num))
		{
			cout << "\n\nEnter higher!";
		}
		if((guess > num)&&(clue < 5))
		{
			cout << "\n\nEnter lower!";
		}
			gotoxy(17, 22);
			cout << "\nYour estimate is:";
			cin >> guess;


		if(guess!= num)
		{
			textcolor(CYAN);
			clue--;
		}
		if(guess == num)
			{
				textcolor(MAGENTA);
				clue = 0;
				l = 1;
				cout << "Wow! You're right! The number is\t" << num;
			}
			
}while(clue!=0);
if(l==0)
{
	cout <<"\nSorry,you failed to guess the number, the number is\t" << num;
	cout <<"\n---------------------------------------------------------";
	cout <<"\n\tWould you like to play again?[Y/N]";
	cin >> answer;
}
if((answer=='N')||(answer=='n'))
{
	clrscr();
	textcolor(GREEN);
	cout<< "\n\n\n\n\t\tYou have chosen to quit. Thanks for playing!" << endl;
}
return 0;
}

I tried what you said about the brackets but the program still doesn't loop. What I really want to happen is that when, for example, I finished the game I then will be asked if I want to play again, once I hit "y or Y" the program should loop. Argh I'm really having a hard time figuring out this thing

I didn't suggested anything about where you should place your brackets. That's your choice

Well, then you should have your game inside a loop. No if I input Yes when your program asks me if I want to play again, then I will jump from line 92 to line 100 (since the conditions on line 94 are both false). Line 100 is the end of main, thus the end of your game.

So, place your game in a do while loop, which will have as condition this

Code:

while(answer != 'N' || answer != 'n');

This way, as long as the user does not input N or n, the code inside the body of the do while I suggest will be executed again. So, if the code is your game, your game will be executed again

Originally Posted by std10093

I didn't suggested anything about where you should place your brackets. That's your choice

Well, then you should have your game inside a loop. No if I input Yes when your program asks me if I want to play again, then I will jump from line 92 to line 100 (since the conditions on line 94 are both false). Line 100 is the end of main, thus the end of your game.

So, place your game in a do while loop, which will have as condition this

Code:

while(answer != 'N' || answer != 'n');

This way, as long as the user does not input N or n, the code inside the body of the do while I suggest will be executed again. So, if the code is your game, your game will be executed again

I already have a do while statement in my program, I tried to put lines 49 to 99 inside another do while statement but I only got an error I don't have any idea where should I put the do while statement you're telling me. Please help me with this.

I don't feel comfortable giving you the direct solution, but I will make an example that does pretty much what you want to do.

I will create an example, that asks the user to guess a number. He has 3 tries available. If he finds the answer, then we will print "Bravo". If not, we will ask him or her if he or she wants to play again. If not, he will terminate by saying goodbye.
Read the code and the comments and then try to modify your main

Code:

#include <iostream>
using namespace std;
 
int main()
{
    int key = 5;
    int input;
    bool found = false; // flag
    char answer;
    int round;
    do {
        // initialize inside the loop, in case
        // we play again
        round = 0;
        do{
            cout << "Please input your guess" << endl;
            cin >> input;
            if(input == key)
            {
                found = true;
            }
            round++;
        }while(round < 3 && !found);
        if(found)
        {
            cout << "Bravo" << endl;
        }
        else
        {
            cout << "Sorry, you lost" << endl;
        }
        cout << "Would you like to play again?"  << endl;
        cin >> answer;
        
        // Different conditions than yours
    }while(answer == 'y' || answer == 'Y');
    
    cout << "Goodbye!" << endl;
    return 0;
}

Of course my code can be improved, but I think you will get the logic

Originally Posted by std10093

I don't feel comfortable giving you the direct solution, but I will make an example that does pretty much what you want to do.

I will create an example, that asks the user to guess a number. He has 3 tries available. If he finds the answer, then we will print "Bravo". If not, we will ask him or her if he or she wants to play again. If not, he will terminate by saying goodbye.
Read the code and the comments and then try to modify your main

Code:

#include <iostream>
using namespace std;
 
int main()
{
    int key = 5;
    int input;
    bool found = false; // flag
    char answer;
    int round;
    do {
        // initialize inside the loop, in case
        // we play again
        round = 0;
        do{
            cout << "Please input your guess" << endl;
            cin >> input;
            if(input == key)
            {
                found = true;
            }
            round++;
        }while(round < 3 && !found);
        if(found)
        {
            cout << "Bravo" << endl;
        }
        else
        {
            cout << "Sorry, you lost" << endl;
        }
        cout << "Would you like to play again?"  << endl;
        cin >> answer;
        
        // Different conditions than yours
    }while(answer == 'y' || answer == 'Y');
    
    cout << "Goodbye!" << endl;
    return 0;
}

Of course my code can be improved, but I think you will get the logic

What specific software are you using sir? I used Turbo C++ version 3.0 because our professor required us to use it. I believe this version do not support boolean type. I'm totally messed up argh . I got errors in line 1 unable to open include file iostream, line 2 declaration syntax error, line 8 undefined symbol bool and statement missing ";" , line 16 undefined symbol and undefined symbol endl, line 17 undefined symbol cin and in line 20 undefined symbol found and undefined symbol true. Would you please give me the answer sir? I'm trying to fix this program for 7 straight hours and I still can't create a solution for this.

Fair warning: you are using an extremely outdated pre-C++ compiler that does not follow the C++ standard. It will be utterly and completely useless in real life.
So I suggest you complete the course as best you can (there is little you can do about the tools most likely, so...) and the completely forget everything. Every little thing you've learned because it's complete and utter nonsense. The best thing you can do it re-learn C++ from the beginning later if/when you need to use it.

And as for a solution, sorry, not going to happen. You are required to be able to properly code a task yourself. Otherwise, you will not learn anything.
The logic - the flow of code - is something that every programmer must know and master. If there any problems in the code, you need to learn how to use a debugger. That, or make a flowchart to trace the flow of the code (not ideal).

The problem is what Elysia states. I wanted to say that the headers you use are really old, but I wanted first you to complete the program.

What is happening is that your compiler does not recognize what mines does.
But, if using this compiler is a must by your professor, then use your own headers to accomplish this program, but then have a conversation with your professor about all this. The headers you are using are what Elysia said.

So, instead of a boolean variable use an int, and represent false as zero and true as 1.
Example of using an int variable as a boolean one.

Code:

int main()
{
      int found = 0;
   
      /* the game */
      
      if(found)
      {
             /* Win */
      }
      else
      {
              /* Lose */
      }
      return 0;
}

So do this, and try to modify your code then