Thread: std::allocator <memory>

  1. #1
    Registered User
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    May 2010
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    std::allocator <memory>

    Not understanding this.

    Code:
    std::allocator<string> alloc;
    auto const p = alloc.allocate(10);
    Results in p have a <Bad Ptr> upon inspection.

    Code:
    std::allocator<string*> alloc;
    auto const p = alloc.allocate(10);
    This is fine. Why is that as well as for integral types like int? C++ Primer has a clear example using a std::string for the templated type of allocator .

  2. #2
    Lurking whiteflags's Avatar
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    Because allocate is enough for plain old data. You want allocator::construct - C++ Reference

    Here's a basic example btw:
    Code:
    #include <memory>
    #include <iostream>
    #include <string>
    
    using namespace std;
    
    int main() {
    
        allocator<string> alloc;
        string* p = alloc.allocate(sizeof *p);
        alloc.construct(p, "hello, world");
    
        cout << *p << endl;
    
        alloc.destroy(p);
        alloc.deallocate(p, 1UL);
    
    }
    Last edited by whiteflags; 02-08-2013 at 04:05 PM.

  3. #3
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    Quote Originally Posted by whiteflags View Post
    Because allocate is enough for plain old data. You want allocator::construct - C++ Reference

    Here's a basic example btw:
    Code:
    #include <memory>
    #include <iostream>
    #include <string>
    
    using namespace std;
    
    int main() {
    
        allocator<string> alloc;
        string* p = alloc.allocate(sizeof *p);
        alloc.construct(p, "hello, world");
    
        cout << *p << endl;
    
        alloc.destroy(p);
        alloc.deallocate(p, 1UL);
    
    }

    So my problem was only allocating and not simultaneously constructing the memory leading to <Bad Ptr>. Ok thank you.

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