Array Problem

This is a discussion on Array Problem within the C++ Programming forums, part of the General Programming Boards category; hi how can i revise the code below so that as well as being able to book a particular hour ...

  1. #1
    Registered User
    Join Date
    Apr 2002
    Posts
    3

    Question Array Problem

    hi

    how can i revise the code below so that as well as being able to book a particular hour in the day, I can also request the first free hour of the day?

    thanks

    #include <iostream.h>
    #include <string.h>
    #include<conio.h>

    struct book
    {
    char time[5];
    bool status;
    };

    //the array
    void makebook(book z[])
    {
    strcpy(z[0].time,"0900");
    strcpy(z[1].time,"1000");
    strcpy(z[2].time,"1100");
    strcpy(z[3].time,"1200");
    strcpy(z[4].time,"1300");
    strcpy(z[5].time,"1400");
    strcpy(z[6].time,"1500");
    strcpy(z[7].time,"1600");
    strcpy(z[8].time,"1700");

    z[0].status=true;
    z[1].status=true;
    z[2].status=true;
    z[3].status=true;
    z[4].status=true;
    z[5].status=true;
    z[6].status=true;
    z[7].status=true;
    z[8].status=true;
    }

    void printbook(book z[])
    {
    for(int i=0;i<9;i++)
    {
    cout<<i+1<<" "<<z[i].time<<"\t";

    if(z[i].status!=true)
    cout<<"Booked"<<endl;
    else
    cout<<""<<endl;
    }
    }

    void main ()
    {
    book ob[9];
    makebook(ob);

    printbook(ob);

    char date[11];

    cout<<"enter the date in dd/mm/yy format : ";
    cin>>date;

    bool ask=true;

    while(ask==true)
    {
    cout<<"Enter number of hour to enter appointment : ";

    int num;
    cin>>num;
    num = num - 1;

    //checks to see if time already booked
    if(ob[num].status==false)
    cout<<ob[num].time<<" is already booked"<<endl;
    else
    {
    cout<<ob[num].time<<" is now booked "<<endl;
    ob[num].status=false;
    }
    cout<<"Enter another appointment ? (y/n) : ";
    char temp;
    cin>>temp;
    if(temp=='n')
    ask=false;
    }
    // display output on monitor
    cout<<"\nAppointments for "<<date<<endl;
    cout<<"\n";
    printbook(ob);
    cout<<"\n";
    }

  2. #2
    Unregistered
    Guest
    It looks like you need to make use of the FOR loop. Not only will this make initialization much cleaner, but you can also use it to detect for an unbooked hour.


    // initialization
    for( int i = 0; i < 8; i++ )
    x[i].status = true;

    I think you've got enough skill to figure out how to check for the first unbooked hour if you use FOR.

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