Thread: C++ Help Me!!!!!!!!

Put this at the top of that program and it should work fine,

Code:

#include <iostream>
using namespace std;

this code is slightly wrong......

Code:

int main(){ 
  cout<<Enter three numbers: "; 
  char *s; 
  cin.getline(s);cin.ignore(); 

  int num1, num2, num3; 
  num1=atoi(s[0]);num2=atoi(s[1]);num3=atoi(s[2]); 
  cout<<num1+num2+num3<<endl; 
  return 0; 
}

The arguements to getline are wrong and you attempt to input into memory you dont 'own'.
here is the same piece of code with fixes....

Code:

#include<iostream>
using namespace std;
int main(){ 
  cout<<Enter three numbers: "; 
  char s[81] 
  cin.getline(s,sizeof(s));cin.ignore(); 

  int num1, num2, num3; 
  num1=atoi(s[0]);num2=atoi(s[1]);num3=atoi(s[2]); 
  cout<<num1+num2+num3<<endl; 
  return 0; 
}

You guys are doing it all wrong. He said 3 DIGIT number, and then add each individual digit. so if you entered 125, you would add 1+2+5 wich equals 8.

However, I do not have time to explain the code. So hopefully you guys can work off of this. If I had a few more minutes, I'd write the code for you. Sorry!

how about getting the input a an array of integers and adding the integers?

a three digit number is a meaningless concept to the compiler. The input could be stored as a string, an int, a double, a float, or any number of variable types. If the requirement was to enter an integer consisting of three digits, then the concepts as presented so far would be off base.

char sEntry[4];
int entry;
cout << "enter a 3 digit number" << endl;
cin >> sEntry;
cout << "enter another 3 digit number" << endl;
cin >> entry;

However, here's a completely different approach that doesn't require conversion from int to string or char to int or any of that stuff:

int num1, num2, num3, i, temp;
int total = 0;
temp = entry;

num3 = temp % 10;
temp = temp/10;//this is integer math, not routine math//
num2 = temp % 10;
num1 = temp/10;
total = num1 + num2 + num3;
cout << "the sum of the digits of the number " << entry << " is " << total << "." << endl;

Oops, looks like Zen beat me to the punch as I was waylaid in my posting my response. Oh well.