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Why can't I do the second method?

This is a discussion on Why can't I do the second method? within the C++ Programming forums, part of the General Programming Boards category; Working method: Code: sf::Vector2i *position = &sf::Mouse::getPosition(); gui.didClickButton(position); Now, that works just fine. But, why can't I just do: Code: ...

  1. #1
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    Why can't I do the second method?

    Working method:

    Code:
    sf::Vector2i *position = &sf::Mouse::getPosition();
    gui.didClickButton(position);
    Now, that works just fine. But, why can't I just do:

    Code:
    gui.didClickButton(sf::Vector2i &sf::Mouse::getPosition());

  2. #2
    Registered User whiteflags's Avatar
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    This is the same error for the same reasons as before.

    You seem to have an issue reading the difference between a pointer expression (&sf::Mouse::getPosition()) and a reference declaration. What I think you need to be told is that a pointer expression is not preceded by a type name, unless it is being cast the C way. Usually pointer expressions can be function arguments or values on the left hand side of an assignment statement. The difference between that and a reference declaration is that a reference declaration is a statement on its own.

    sf::Vector2i& reference;
    Normally you wouldn't try to use this exact statement as a pointer argument.
    Justin H likes this.

  3. #3
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    Aha, never mind. I understand now. Can't believe I didn't figure that one out. >.<

    It's:

    Code:
    gui.didClickButton(&sf::Mouse::getPosition());
    Thanks. ^.^

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