what is difference in these two codes as they are giving different outputs..??
Code:circle operator=(circle c) { circle t; t.radius=c.radius; t.x=c.x; t.y=c.y; return t; }Code:circle operator=(circle c) { radius=c.radius; x=c.x; y=c.y; return circle(radius,x,y); }
I am assuming both of those function definitions are within the definition for class circle. Otherwise, both samples will give a compilation error.
Given an expression "lhs = rhs;" (where lhs and rhs are both of type circle) the first version does not change lhs. The second one does.
Conventionally, assignment operators accept an argument that is a const reference, and return a reference. Rather than (as in both your cases) accepting an argument by value and returning a value.
Conceptually, you are missing the fact that assignment operators are member functions, with an implied "this" pointer.
