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  • 1 Post By oogabooga

no accepting my loop

This is a discussion on no accepting my loop within the C++ Programming forums, part of the General Programming Boards category; /I am writting a menu program that lets the user select from a list of options, and if the input ...

  1. #1
    Registered User
    Join Date
    Oct 2012
    Posts
    3

    no accepting my loop

    /I am writting a menu program that lets the user select from a list of options, and if the input is not one
    /of the options, reprint the list.

    /Its not accepting my loop

    Code:
     #include <iostream>
    using namespace std;
    int main ()
    {
    int a, b, c, x1, x2 ;
    cout << "Please select from the following a, b, c \n";
    cin >> x1;
    
    while ( ! x2 == a || ! x2 == b || ! x2 == c );
    {
    cout << "Please select again \n" ;
    cin >> x2;
       }
         cin.get ();
    }
    Last edited by Reggie Green; 10-14-2012 at 07:10 PM.

  2. #2
    - - - - - - - - oogabooga's Avatar
    Join Date
    Jan 2008
    Posts
    2,808
    You may mean something like this:
    Code:
    #include <iostream>
    using namespace std;
    
    int main () {
        char x;
        cout << "Please select from the following a, b, c \n";
        cin >> x;
        while ( ! (x == 'a' || x == 'b' || x == 'c') )
        {
            cout << "Please select again \n" ;
            cin >> x;
        }
        cin.get ();
        return 0;
    }
    You need to read your book more because you seem to have many misunderstandings.
    Reggie Green likes this.
    The cost of software maintenance increases with the square of the programmer's creativity. - Robert D. Bliss

  3. #3
    Registered User
    Join Date
    Oct 2012
    Posts
    3
    Thank you for help. I am trying I have been studying so eventually I will get it.

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