Thread: Error: non constant expression

Hi all,

I am trying to do the following in C++

[code]
static const int data

Code:

={status_1 : 32,
status_2 : 192,
status_3 : 35
};

typedef enum int [data[status_1]-1:0] {
enum_value = 2,
enum_value = 4
};

When i try to compile the above code in C++, I get the error as:
Error: Non constant expression
The following expression should be a constant.
Expression: data[status_1]

How can I access the value '32' from above array??

Sorry i missed one part in it.. Here is the complete code:

Code:

typedef enum {
status_1 = 'h12,
status_2 = 'h14,
status_3 = 'h15
} instruction;

static const int data[instruction] ={status_1 : 32,
status_2 : 192,
status_3 : 35
};

typedef enum int [data[status_1]-1:0] {
enum_value = 2,
enum_value = 4
};

Gosh, this looks like so much jibberish. Are these supposed to be bitfields?

Code:

static const int data
={status_1 : 32,
status_2 : 192,
status_3 : 35
};

That's what they look like. Unfortunately only struct members can be bitfields. Nothing you've written is like an array, either.

What are you trying to do in English?

i completed the code in the second post.

Code:

static const int data[instruction] ={status_1 : 32, 
status_2 : 192, 
status_3 : 35 
};

Mhmmm ok.

If you just want that to compile you would have to make 'instruction' a constant expression. Try declaring it as a constant integer and assigning a value, then use 'instruction' to make your fixed array. Arrays cannot be used as bitfields. In the initialization list, the expressions used have to be ints, so you could probably use status_1 etc, or 32, but not both. And not with a colon, that does not mean what you think it does.