G[u].push back(v);
here G[5] is a vector
u,v are int
This is a discussion on In vector what does it mean? within the C++ Programming forums, part of the General Programming Boards category; G[u].push back(v); here G[5] is a vector u,v are int...
G[u].push back(v);
here G[5] is a vector
u,v are int
Manasij Mukherjee | gcc-4.9.2 @Arch Linux
Slow and Steady wins the race... if and only if :
1.None of the other participants are fast and steady.
2.The fast and unsteady suddenly falls asleep while running !
I want to konw how:Code:#include <algorithm> #include <iostream> #include <vector> using namespace std; const int MAXN = 100; int A[MAXN], B[MAXN]; vector<int> g[MAXN]; bool second_high_to_low(pair<int, int> a, pair<int, int> b){ if (a.second != b.second) return a.second > b.second; return a.first < b.first; } pair<int, int> f(int u, int dad = -1){ vector< pair<int, int> > p; for (int i = 0; i < g[u].size(); ++i){ int v = g[u][i]; if (v == dad) continue; p.push_back( f(v, u) ); } sort(p.begin(), p.end(), second_high_to_low); int total = A[u]; int inhand = A[u] - B[u]; for (int i = 0; i < p.size(); ++i){ if (inhand > p[i].first){ inhand -= p[i].first - p[i].second; }else{ total += p[i].first - inhand; inhand = p[i].second; } } return make_pair(total, inhand); } int main(){ int n, Case = 1; while (cin >> n){ if (n == 0) break; cout << "Case " << Case++ << ": "; for (int i = 0; i < n; ++i){ int x, y, z; cin >> x >> y >> z; A[i] = x; B[i] = y + z; A[i] = max(A[i], B[i]); g[i].clear(); } for (int i = 0; i < n - 1; ++i){ int u, v; cin >> u >> v; u--, v--; g[u].push_back(v); g[v].push_back(u); } int ans = 3000; for (int i = 0; i < n; ++i){ pair<int, int> p = f(i); ans = min(ans, p.first); } cout << ans << endl; } return 0; }is transfered toCode:pair<int, int> p = f(i);it is really confusing......Code:pair<int, int> f(int u, int dad = -1){also g was declared asCode:how f(i) becomes f(int u,int dad=-1)?Please helpCode:vector<int> g[MAX]; how come it becomes g[u][i];?
It's a C++ feature called default arguments. Unless you provide a different argument for dad, it will be -1 in the function. What's the reason, you think? A default argument is a good way to add functionality or a fix to a function working in existing code without breaking existing code.
It's inherent in the type of g. An array of vectors can be indexed that way.also g was declared asPlease helpCode:vector<int> g[MAX]; how come it becomes g[u][i];?
Please help yourself to the detailed reference on the web you were linked earlier.
Last edited by whiteflags; 09-27-2012 at 11:58 PM.
You're an idiot. He asks about both vectors and default arguments in his post. All you have to do is read his code to notice this, but I will explain my answer.
f() is a function.
pair<int, int> is the return value, f is the function name, and there's the parameter list "(int u, int dad = -1)". dad = -1 in this context is a default argument. You can also see the function body.
I mean, if I read the question wrong, you're welcome to put some effort in and actually correct me.Originally Posted by enakta13
But I also answer his other question.
Perhaps I didn't answer it well, but what could I do? It would be nice if he knew more words.Originally Posted by enakta13