Thread: Iterating over multi map

Hi,

I have a problem trying to iterate over a multimap (or rather map within map).

I have this:

Code:

#include <map>

using namespace std;

int main(){
map<string, map<string, string> > mymap;
map<string, map<string, string> >::iterator itm;

/* This is how I would iterate over a normal map;
for( it=mymap.begin(); it!=mymap.end(); ++it)
{
cout << "first: \t" << it->first << "second: \t" << it->second << endl;
}

OR

cout << mymap.find("ab")->second << endl;
*/

return 0;
}

But for a map within a map it won't work.

Can someone help?


Thanks.

Originally Posted by coderplus

But for a map within a map it won't work.

What won't work? Please post an example of what you expect to work, and in what respect it is not working. Does it not compile, or does it just not produce the right results?

That is obvious.

As per example I have given, iterating over a normal map, trying to produce the same results with a map within a map doesn't work.

Yes, of course it can iterate fine over the first map but I want to iterate over the second map.

Originally Posted by coderplus

Yes, of course it can iterate fine over the first map but I want to iterate over the second map.

Iteration over the second map works the same way as for the outher map.
Without you showing what is not working we will not get anywhere here.
Kurt

OK so if I had:

Code:

for( itm=mymap.begin(); itm!=mymap.end(); ++itm)

{
cout << "first: \t" << it->first << endl;

}

That to iterate over the first map, how would I get to the second map?

Originally Posted by coderplus

OK so if I had:

Code:

for( itm=mymap.begin(); itm!=mymap.end(); ++itm)

{
cout << "first: \t" << it->first << endl;

}

That to iterate over the first map, how would I get to the second map?

Do the same; just do it over the second map.

(Hint: Show us code, or it looks an awful lot like you're trying to get us to do your homework for you.)

It has nothing to do with homework.

And I posted the code I was working on.

Nevermind, I have figured it out.