Approximating PI using the Taylor Series - Help!

I don't care - would just do 4 * arctan(1.0) anyway.

I'd just use a constant.

Soma

Originally Posted by phantomotap

I'd just use a constant.
Soma

Solution found

Originally Posted by phantomotap

I'd just use a constant.

Soma

I like M_PI from math.h.
But, so far I have never needed it and had the compiler I was using supply it at the same time.

Tim S.

I might do the loop more like this:

Code:

double numerator = -1.0
double taylor = 1.0;
for (int i = 3; i < terms; i+=2, numerator *= -1)
{
    taylor += numerator/i;
}

but to each his own.