Question about using an vector iteration loop in C++---Running Mean with three values

This is a discussion on Question about using an vector iteration loop in C++---Running Mean with three values within the C++ Programming forums, part of the General Programming Boards category; I am trying to figure out a general form of this hypothetical example using C++. I have a vector with ...

  1. #1
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    Exclamation Question about using an vector iteration loop in C++---Running Mean with three values

    I am trying to figure out a general form of this hypothetical example using C++.

    I have a vector with any three numbes. I want the first numbers and third numbers in the vectors to not be changed, however for the second number, I would like the number to be average with the first number, the second number, and the third number in the vector which will replace the second number in the final output.

    I was wondering if iostream <vector> approach is necessary?

    Code:
    #include <iostream>
    #include<vectors>?
    using namespace std;
    
    int main()
    
    {
    
    const int numberofterms=3
    double Temperature[numberofterms]={22,24,16.2}
    float average
    
    If (first vector number and third vector number are chosen:) THEN
    
    The first vector and the third vector are kept. 
    
    Else The second vector will be replaced by the average.
    
    average = (Temperature[0]+Temperature [1]+Temperature [2])/numberofterms;
    
    }
    The displaying part would not be a problem but just the way to write this in C++ I am having a really difficult time to find examples of what I am looking for. Thanks again.!

  2. #2
    C++ Witch laserlight's Avatar
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    What do you mean by "iostream <vector> approach"?
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    I see some of the examples using iostream <vector> is that necessary?

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    C++まいる!Cをこわせ!
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    What examples, and where?
    Quote Originally Posted by Adak View Post
    io.h certainly IS included in some modern compilers. It is no longer part of the standard for C, but it is nevertheless, included in the very latest Pelles C versions.
    Quote Originally Posted by Salem View Post
    You mean it's included as a crutch to help ancient programmers limp along without them having to relearn too much.

    Outside of your DOS world, your header file is meaningless.

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    C++ Witch laserlight's Avatar
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    Sorry, but I don't understand what you mean by "iostream <vector>". Basically, if you have a vector of 3 numbers named x, you can use them by accessing x[0], x[1] and x[2]. You can print them like that too.
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    Registered User R41D3N's Avatar
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    I guess he means something like:

    Code:
    #include <iostream>
    #include <vector>

    And nop that wouldnt be necessary, since its just 3(size fixed) values. You might as well use an array of size 3.

    a[0], a[1], a[2] would be the elements.

    Code:
    a[2] = (a[0]+a[1]+a[2])/3; // for the mean
    -- reserved for when I come up with 1 --

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    let me show you what I am talking about: for loop and vectors - C++ Forum

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    C++ Witch laserlight's Avatar
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    Oh, as in use a loop to print the elements of a vector? Sure, you can use that. You don't have to, but you can.
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    so how would the if and else loops work in this case @R41D3N?

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    Registered User R41D3N's Avatar
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    just tell the user to enter the element he wants to switch with the average ... lets say x(0/1/2)

    then your lhs would become

    Code:
    a[x] = ....

    You could work vectors the same way, if thats what you are aiming for ...
    Last edited by R41D3N; 06-19-2012 at 11:40 AM.
    -- reserved for when I come up with 1 --

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    Code:
    #include <iostream>
    
    #include<vectors>?
    using namespace std;
     
    int main()
     
    {
     
    const int numberofterms=3
    double T[numberofterms]={22,24,16.2}
    
    float average
    
     
    If (T[1], T[3]) 
    
     
    
    cout<<T[1]<<endl;
    cout<<T[2]<<endl;
    
    Else If (which should assume T[2] if I am correct)
    T[2] = (T[0]+T[1]+T[2])/3
    
    }
    of course System("PAUSE") Return0.

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    actually I meant for line 24: T[2] = (T[0]+T[1]+T[2])/numberofterms

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    At least that's my way of "understanding" what you are trying to say. I know its wrong. LOL.

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    Registered User R41D3N's Avatar
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    Quote Originally Posted by Rod Micael View Post
    [
    of course System("PAUSE") Return0.
    dont use system() . If you want to hold the display screen, better use cin.get();

    the way I suggested it, you wouldnt need an if-else block. Rather than user choosing which 2 to keep as is, let them choose which element to modify into the average. So as to get the index.
    -- reserved for when I come up with 1 --

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    Quote Originally Posted by R41D3N View Post
    dont use system() . If you want to hold the display screen, better use cin.get();

    the way I suggested it, you wouldnt need an if-else block. Rather than user choosing which 2 to keep as is, let them choose which element to modify into the average. So as to get the index.
    Code:
    #include <iostream>
     
    #include<vectors>?
    using namespace std;
      
    int main()
      
    {
      
    const int numberofterms=3
    double T[numberofterms]={22,24,16.2}
     
    float average
     
      
    If (T[1], T[3]) 
     
      
     
    cout<<T[1]<<endl;
    cout<<T[2]<<endl;
     
    Else If 
    
    T[2] = (T[0]+T[1]+T[2])/numberofterms
    
    cin.get()
    return 0;
    
    
     
    }
    Would this be a correct approach?

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