Check??Newbie..HELP!!

**sweets** · 04-07-2002

you can test for int's easily but char's and string's are a different story. you must not forget that a char can be anything that can be inputted via the keyboard....including numbers, symbols and characters.

if you are more specific with what you are after I might be able to help you...but as I said, I need to know exactly what it is you want to do.

ohh...just another thing that just clicked to me....you can do a something like this which will only continue until a valid char input has been made.

Code:

char ch;

  do
  {
     cout << "pls select from the following " << endl;
     cout << " a)  add another word " << endl;
     cout << " b)  find word" << endl;
     cout << " c)  exit " << endl;
     cin >> ch;

    switch (ch)
    {
        case 'a' :  addData();   //go to a fnt
                        break;
        case 'b' :  findData ();
                        break;
    }
  } while (ch != 'c');

hope this helps...

Unregistered · 04-07-2002

My expected code:

Code:

string s1="end";
   do {
	  
      cout << "Enter name:";
      cin >> name;
      if (name==s1) //this is working
         break;

	  //while ((name doesnt has alphabets))
	       cout<<"error"
                               <<"ur string has a number in it"<<endl;
		  cout<<"please re-enter the name"<<endl;
		  cin>>name;//

this is my first doubt..

also there is a minor bug,which is buggin me ,as per ur previous code for checking ONLY int ,

Code:

cout << "Enter 1st time:";
      cin >> a_time;
	  while (cin.fail())
 {
    cin.clear();
    cin.ignore (buffer, '\n');
    cout << "pls re-enter number";
    cin >>a_time;       //now for eg if i type 12A  the  output  is "enter   2nd time", pls re-enter number" ie. how should i avoid getting the display message"enter 2nd time"??//
 } 

 cout << "Enter 2nd time:";
      cin >> b_time;
	  while (cin.fail())
 {
    cin.clear();
    cin.ignore (buffer, '\n');
    cout << "pls re-enter number";
    cin >>b_time;
 }

thanks ......

**sweets** · 04-07-2002

if the user was to input 132A your program will accept and only assign 132 to your a_time...if the user had inputted A123 then cin.fail() would return true and ask you to re-enter the value.

if the user was to input 12ABC34, then a_time would hold the value of 12 and ignore the rest.

as for your function with strings...firstly you cant have string s1="end" unless you pre-define it. dont forget a string is just an array of characters terminated with a '\0' character.

string.h library has a variety of string operations you can use. for example, instead of doing name==s1 (which I dont think should work unless everything is implemented properly) you can and should really get use to doing something like :

result=strcmp(str1, str2);

result will contain a -ve number if str1 < str2
result will contain a +ve number if str1 > str2
result will contain a zero if str1==str2

and then you can put in your conditions according to what result returns. you can find alot of information in regards to string handling if you look through a text book dealing with c++.

something I just remembered may also be useful....try something like this :

if (letter < 'a' || letter > 'z')

this may also help with what you want

sophie

Unregistered · 04-07-2002

Unfortunately sophie thats not the case,
if i type 13a /13A ,
its showing me the next cout statement; in my case
"enter 2nd TIME"//which is the time in seconds//
and next line its coming "please reenter number"

also checking of strings, i have predefined
string s1="end" ,before int main()
and its working nicely.

i have used find_first_of funcn,which checks that input is a string but i just dont know how to put it in a while loop,to ask the user to reenter the name
my present code:

Code:

in chk=0;
int main()
.
.
chk= name.find_first_of("1234567890");
	  if(chk!=-1)
	  {
		  cout<<"error!"
	                      <<"ur string has a number in it";
	  }

thanks .......

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